well you cant really be expecting us to answer all that, so make sure you specify exactly WHAT you want to be answered.
62. -2(x - 1) + 5x = 2(2x - 1)
...multiply -2
-2x + 2 + 5x = 2(2x - 1)
...multiply 2
-2x + 2 + 5x = 4x - 2
...simplify
3x + 2 = 4x - 2
...add 2
3x + 4 = 4x
...subtract 3x
4 = x
I'm pretty sure DEF is a scalene triangle since it looks like none of the sides are equal to each other.
Hope this helps!
May
Answer:
Lamda= 4 students/min, µ= 5 students/min
P= Lamda/µ= 4/5= 0.8
a.) Probability that system is empty= P0= 1-P= 1-0.8= 0.2
b.) Probability of more than 2 students in the system= ∑(n=3 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2)= (.2)*(5- - .2 - (.8)*.2 – (.2)*.8^2))= 0.848
Probability of more than 3 students in the system= ∑(n=4 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2 – (1-P)*P^3)= 0.768
c.) W(q)= Waiting time in Queue= lamda/µ(µ- lamda)= 4/5(1)= 0.8 minutes
d.) L(q)= lamda*W(q)= 4*.8= 3.2 students
e.) L(System)= lamda/(µ-lamda)= 4 students.
f.) If another server with same efficiency as the 1st one is added, then µ= 6 sec/student= 10 students/min.
P= 4/10= 0.4
Probability that system is empty= P0= 1-.4= 0.6
W(q)= 4/10(10-4)= 0.0667 minutes
L(q)= Lamda*W(q)= 4*.0667=0.2668
L(system)= Lamda/(µ-lamda)= 4/6= .667
Step-by-step explanation:
It would take the willy-nilly bike club 4 days to ride from one end of the trail to the other
