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aalyn [17]
3 years ago
8

Mei bought a box of markers for b dollars, a shoulder bag that cost twice as much as the box of markers and a pen that cost $6 l

ess than the shoulder bag. Write the cost of the pen in terms of b.
Mathematics
1 answer:
Masteriza [31]3 years ago
3 0
Box of markers = $ B

Shoulder bag =  Twice as much as the box of markers = $ 2B

Pen = Six less than the shoulder bag = $ (2B - 6)

Hence, the cost of pen is $ (2B - 6).
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10. Write a word problem for this equation:<br> n ($25) = $125
Andrei [34K]

Answer:

The word problem is "How many $25 are there in $125?"

<em></em>

Step-by-step explanation:

Given

n(\$25) = \$125

Required

Write a word problem for the expression

We start by solving the given equation

n(\$25) = \$125

Divide both sides by $25

\frac{n(\$25)}{\$25} = \frac{\$125}{\$25}

n = \frac{\$125}{\$25}

n = 5

This implies that there are 5, $25 in $125

<em>Hence; The word problem is "How many $25 are there in $125?"</em>

6 0
3 years ago
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng
gladu [14]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

AREA = ANGLE   \: \: IN  \: \:  RADIAN  \times RADIUS

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Total Area Of The Semi Sphere:-

AREA =   \pi \times radius  \\  \\ AREA = \pi \times 2 = 2\pi

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

AREA =  \frac{\pi}{3}  \times radius \\  \\ AREA =  \frac{\pi}{3}  \times 2 \\  \\ AREA =  \frac{2\pi}{3}

\green{Now:- } \\  \green{ \: Area  \: Under \:  Unshaded \:  Part }

Total Area - Area Under Unshaded Part

Area= 2\pi -  \frac{2\pi}{3}  \\ Area =  \frac{6\pi - 2\pi}{3}   \\ Area =  \frac{4\pi}{3}  \:  \: ans

\red \star{Thanks \:  And  \: Brainlist}  \blue\star \\  \green\star  If \:  U  \: Liked \:  My  \: Answer \purple \star

5 0
2 years ago
What is 16500 rounded to the nearest ten thousand?
frosja888 [35]
16500 Rounded to the nearest ten thousand is 20,000
4 0
3 years ago
Please Explain How To Solve This
atroni [7]

Answer:

Step-by-step explanation:

domain is always the x-values, the first number of an ordered pair. and yes, the x and y values increase at a constant rate.

problem #1:

x   /   y

-2     -1

-1      -3

0      -5

1       -7

problem #4:

(5, 1) (6, 2) (7, -3) (8, 4) (9, 5)

hope this all helped ;)

mark me brainliest :D

4 0
3 years ago
Read 2 more answers
The combined area of two squares is 80 square centimeters. Each side of one square is twice as long as a side of the other squar
o-na [289]

The length of each side of the larger square is 8 cm.

<u>Step-by-step explanation</u>:

Step 1 ;

  • The combined area of two squares = 80 sq.cm
  • The side of small square = x
  • The side of larger square = 2x

Step 2 :

Area of the square = a^2

Area of small square + area of large square = 80

x^2 + (2x)^2 = 80

x^2 + 4x^2 = 80

5x^2 = 80

x^2 = 80/5

x^2 = 16

x = ±4

Step 3 :

Since length cannot be negative, the value of x= 4

∴ The length of the side of small square = 4cm

The length of the side of larger square = 2x = 8cm

5 0
3 years ago
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