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Hitman42 [59]
3 years ago
14

What is the solution of the equation? (√2x-1) + 2=x

Mathematics
1 answer:
Gwar [14]3 years ago
7 0

Answer:

x = 5

Step-by-step explanation:

√(2x − 1) + 2 = x

√(2x − 1) = x − 2

2x − 1 = (x − 2)²

2x − 1 = x² − 4x + 4

0 = x² − 6x + 5

0 = (x − 1) (x − 5)

x = 1 or 5

Check for extraneous solutions.

√(2(1) − 1) + 2 = 1

√(1) + 2 = 1

3 = 1

No solution

√(2(5) − 1) + 2 = 5

√(9) + 2 = 5

5 = 5

x = 5

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Can somebody help me on 23 and 24, it’s geometry
Luda [366]

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Step-by-step explanation:

As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE

<u>Question number 23:</u>

Given

DS = 3x+10

SE = 6x-2

As the two segments are equal:

DS = SE\\3x+10 = 6x-2

Subtracting 10 from both sides

3x+10-10 = 6x-2-10\\3x = 6x-12

subtracting 6x from both sides

3x -6x = 6x-6x-12\\-3x = -12

Dividing both sides by -3

\frac{-3x}{-3} = \frac{-12}{-3}\\x = 4

Now

DS = 3x+10\\= 3(4)+10\\= 12+10\\=22

And

SE = 6x-2\\= 6(4)-2\\= 24 - 2\\=22\\DE = DS+SE\\= 22+22\\=44

<u>Question No 24:</u>

Given

DS = x+3

DE = 56

We know that:

DS = \frac{1}{2}DE\\x+3 = \frac{56}{2}\\x + 3 = 28\\x = 28-3\\x = 25

So

DS = 25+3 = 28

As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

4 0
3 years ago
The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
3 years ago
The number of the x is 5 and the number of the Y
Readme [11.4K]

Answer:

Y is also 5 bro that is very easy question

4 0
3 years ago
Read 2 more answers
A) For AQRS use the Triangle Proportionality Theorem to solve for x.
xenn [34]

Answer:

a. x = 14

b. Perimeter = 77

Step-by-step explanation:

a. Based on the Triangle Proportionality Theorem:

\frac{2x - 2}{13} = \frac{21 - 7}{7}

\frac{2x - 2}{13} = \frac{14}{7}

\frac{2x - 2}{13} = 2

Cross multiply

2x - 2 = 2(13)

2x - 2 = 26

Add 2 to both sides

2x = 26 + 2

2x = 28

Divide both sides by 2

x = 14

b. Perimeter of ∆QRS = RQ + QS + RS = (2x - 2) + 13 + 17 + (21 - 7) + 7

Plug in the value of x

= (2(14) - 2) + 13 + 17 + 14 + 7

= 26 + 13 + 17 + 14 + 7

= 77

8 0
2 years ago
For what values of c does the binomial 5-3c take on a value which is greater than 80?
Ganezh [65]
Answer: c > -25

From the question you can get the equation:
5 - 3c > 80; subtract 5 from both side
-3c > 75; divide -3 from both side
c > -25
So numbers including: -24, -23, -22, -21…
are all numbers that could work
7 0
2 years ago
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