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marin [14]
3 years ago
5

Given the points (-1, 1) & (-2,-5), what is the equation of the line? *

Mathematics
1 answer:
Leni [432]3 years ago
3 0

Answer:

Y=6x+7

Step-by-step explanation:

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Someone please help ASAP!!!
WITCHER [35]

Answer:

I'm here, what do you need help with?

Step-by-step explanation:

6 0
3 years ago
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n200080 [17]

Answer: 33%

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2 years ago
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Fill out the information below for the following graph of a quadratic function. Please Help!!
Inessa [10]

Answer:

Please refer to the images attached below.

Step-by-step explanation:

Quadratic Functions are functions of degree 2. The graph of any quadratic function is a parabola that has a vertex and axis of symmetry.

Some Properties of Graph Translations

1. y=a(x-h)^2+ky=a(x−h)

2

+k

This means that the new function is translated h units to the right and k units going up.

2. y=a(x-h)^2-ky=a(x−h)

2

−k

This means that the new function is translated h units to the right and k units going down.

3. y=a(x+h)^2+ky=a(x+h)

2

+k

This means that the new function is translated h units to the left and k units going up.

4. y=a(x+h)^2-ky=a(x+h)

2

−k

This means that the new function is translated h units to the left and k units going down.

First, let's graph the function y=3x^2+3y=3x

2

+3 . The vertex is at the point (0,3)(0,3) . Please refer to Figure 1 below.

Now, start from the vertex of the first function, (0,3)(0,3) , as you notice that the function y=3(x-3)^2+1y=3(x−3)

2

+1 is 3 units translation to right and one unit translation going up. This means that the new vertex is the point (3,1)(3,1) .Please refer to Figure 2.

For the function, y=3(x+3)^2-1y=3(x+3)

2

−1 , start from the vertex of the first function, (0,3)(0,3) , then make a translation of 3 units to the left and a translation of 1 unit down. This gives us a new vertex of (-1, -3)(−1,−3) . Please refer to Figure 3.

#LetsStudy

To learn more about quadratic functions, go to

https://brainly.ph/question/2436149

https://brainly.ph/question/4568410

https://brainly.ph/question/5982152

Step-by-step explanation:

<em>FOLLOW</em><em> </em><em>ME </em><em>OKAY </em><em />

<em>I </em><em>WILL</em><em> FOLLOW</em><em> </em><em>YOU</em><em> </em><em>BACK</em><em> </em><em />

6 0
2 years ago
Y =  7x + 43
Paul [167]
Hi there! The answer is A. (-6, 1)

y = 7x + 43 \\ y = 2x + 13 \\ \\ we \: get \: the \: following \\ 7x + 43 = 2x + 13

Subtract 2x from both sides.
5x + 43 = 13

Subtract 43 from both sides.
5x = - 30

Divide both sides by 5.
x = - 30 \div 5 = - 6

Fill in the value of x we just found.
y = 7 \times - 6 + 43 = - 42 + 43 = 1 \\ y = 2 \times - 6 + 13 = - 12 + 13 = 1

Hence, the answer is A. (-6, 1)
7 0
3 years ago
Calculate the present value of the annuity. (Round your answer to the nearest cent.)
timama [110]

Answer:

Ans. the present value of $1,300/month, at 6.4% compounded monthly for 360 months (30 years) is $207,831.77

Step-by-step explanation:

Hi, first, we have to turn that 6.4% compound monthly rate into an effective rate, one that meets the units of the payment, in our case, effective monthly, that is:

r(EffectiveMonthly)=\frac{r(CompMonthly)}{12} =\frac{0.063}{12} =0.005333

Therefore, our effective monthly rate is 0.5333%, and clearly the time of the investment is 30 years*12months=360 months.

Now, we need to use the following formula.

Present Value=\frac{A((1+r)^{n}-1) }{r(1+r)^{n} }

Everything should look like this.

Present Value=\frac{1,300((1+0.005333)^{360}-1) }{0.005333(1+0.005333)^{360} }

Therefore

PresentValue=207,831.77

Best of luck.

6 0
3 years ago
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