3 years ago

Find the sum of the first 10 terms of the series -3 +12-48+....,

1 answer:

3 0

R= -4
a= -3
using ∑n = a(1-rⁿ)/1-r
∑n:10 = -3(1-(-4)^10)/ 1-(-4)
= -3(1-1,048,576)/1+4
= -3(-1048575)/5
= 3,145,725/ 5
= 629,145

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