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grandymaker [24]

3 years ago

6

While bird watching gabrielle saw 6 robins and 3 blue jays. Chase saw 3 robins and 6 blue jays. Who saw more birds? Tell which p

roperty you used.

1 answer:

Serjik [45]3 years ago

4 0

They both saw the same amount because 6+3 = 9 and 3+6 = 9

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Firdavs [7]

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I can't get to get this right can you please help me

monitta

Answer:

$(-7,4]\text{ or }\{x|-7$

Step-by-step explanation:

The domain is the span of x-values covered by the function.

From the graph, we can see that the graph covers all the x-values from x=-7 to x=4.

However, note that closed and open circles. There is an open circle at x=-7, which means that the domain excludes x=-7. However, the circle at x=4 is closed, meaning it is included in the domain.

Therefore, the domain is, in interval notation:

$(-7,4]$

We use parentheses on the left because we do not include -7. And we use brackets on the right because we <em>do </em>include the 4.

And in set notation, this is:

$\{x|-7$

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We can write the formula as
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Naddik [55]

Answer:

$X \sim N(114.8,13.1)$

Where $\mu=114.8$ and $\sigma=13.1$

We are interested on this probability

$P(X>140)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

And we can find this probability using the complement rule:

$P(z>1.924)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(114.8,13.1)$

Where $\mu=114.8$ and $\sigma=13.1$

We are interested on this probability

$P(X>140)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this: $P(X>140)=P(\frac{X-\mu}{\sigma}>\frac{140-\mu}{\sigma})=P(Z>\frac{140- 1114.8}{2.6})=P(z>1.924)$ And we can find this probability using the complement rule:

$P(z>1.924)=1-P(z$

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4 years ago