2 years ago

If /\PQR~/\SQT, find the value of x.

Mathematics

1 answer:

worty [1.4K]2 years ago

7 0

Answer:

$\frac{x + 13}{8} = \frac{21}{x - 9} \\ {x}^{2} + 4x - 117 = 168 \\ {x}^{2} + 4x - 285 = 0 \\ (x - 15)(x + 19) = 0 \\ x = 15 \\ x = - 19$

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