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3 years ago

If /\PQR~/\SQT, find the value of x.

Mathematics

1 answer:

worty [1.4K]3 years ago

7 0

Answer:

$\frac{x + 13}{8} = \frac{21}{x - 9} \\ {x}^{2} + 4x - 117 = 168 \\ {x}^{2} + 4x - 285 = 0 \\ (x - 15)(x + 19) = 0 \\ x = 15 \\ x = - 19$

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3 years ago

20n -5 - 3n + 10 pls help

artcher [175]

Answer:

17x+5

Step-by-step explanation:

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3 years ago

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Which 3-D object is a polyhedron?<br> A. sphere<br> B. cube <br> C. cone

Levart [38]

Answer:

The answer is A.

Step-by-step explanation:

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2 years ago

The angle of elevation to the top of a water tower from point A on the ground is 19.9°. From point B, 50.0 feet closer to the to

zepelin [54]

Answer:

Answer in terms of a trigonometric function :

$h = \frac{20tan(19.9)}{0.4-tan(19.9)}$

Answer in figures

$h = 190.5 feet$

Step-by-step explanation:

Consider the sketch attached below to better understand the problem.

Let x be the distance between point B and the base of the water tower.

$tan (19.9)=\frac{h}{50+x} ---------------equation 1\\$

$tan (21.8)=\frac{h}{x}----------------equation 2$

From equation 2,

$x =\frac{h}{tan21.8}=\frac{h}{0.4}$

substituting the value of x into equation 1, we get

$tan (19.9)=\frac{h}{50+(\frac{h}{0.4} )}$

$tan 19.9=h\times \frac{0.4}{20+h}$

cross multiplying,

$20\times tan(19.9) +htan(19.9)=0.4h$

$20tan(19.9)= h(0.4-tan(19.9))$

$h= \frac{20tan (19.9)}{0.4-tan (19.9)}$

The height of the tower is $h= \frac{20tan (19.9)}{0.4-tan (19.9)}$ in terms of the trig function "Tan"

The equation can simply be evaluated to get the answer in figures since the angles are given in the question

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3 years ago

For a spear with a radius of 8 what is the surface area

UkoKoshka [18]

Solution
A=4πr2=4·π·82≈804.24772
Approximately = 804.25

6 0

3 years ago