3 years ago

If /\PQR~/\SQT, find the value of x.

1 answer:

7 0

Answer:

$\frac{x + 13}{8} = \frac{21}{x - 9} \\ {x}^{2} + 4x - 117 = 168 \\ {x}^{2} + 4x - 285 = 0 \\ (x - 15)(x + 19) = 0 \\ x = 15 \\ x = - 19$

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Hey!

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sattari [20]

Use the chain rule:

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Drupady [299]

Answer:

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Step-by-step explanation:

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nikdorinn [45]

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DENIUS [597]

Are you sure your in high school, also it's answer #3.

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