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forsale [732]
3 years ago
10

If /\PQR~/\SQT, find the value of x.

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

\frac{x + 13}{8}  =  \frac{21}{x - 9}  \\  {x}^{2}  + 4x  - 117 = 168 \\  {x}^{2}  + 4x   - 285 = 0 \\ (x - 15)(x + 19) = 0 \\ x = 15 \\ x =  - 19

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