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Brilliant_brown [7]
2 years ago
12

The school talent she is 90 minutes long. The average rate of the show is about 10 acts every 30 minutes. At this rate, how many

acts will be in the talent show
Mathematics
1 answer:
IceJOKER [234]2 years ago
7 0
90/30 = 3

3 x 10 = 30

30 acts
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Monthly earnings total $4513. Find the social security tax deducted.
levacccp [35]
<span>The monthly earning is = 4513 dollars.
Find the security tax.
in US, 3% is the security tax.
3% = 3% / 100 = 0.03
NOw, let's solve with this given digits.
=> 4513 * .03 = 135.39
=> 135.39
Therefore the tax deducted to your salary is 135.39 dollars per month.


</span>
4 0
3 years ago
What is the measure of &lt;1?
Paraphin [41]

Answer:

the measure of ∠1 is 92 degrees

Step-by-step explanation:

6 0
2 years ago
Hey, I need help BAD!! I am doing PEMDAS. 7+(5times6)45+9<br><br><br> Please help me!! Thanks!
leonid [27]

Answer:1

<h2>1,366</h2>

Step-by-step explanation:

P - parenthsis

E - exponents

M - multiplication

D - division

A - addition

S - subtraction

<h3>STICK TO THE ORDER:</h3>

7 + 5 x (6 x 45) + 9 = 1,336 ( Not the pemdas order)

But,

<h3>7 + (5 x 6)45 + 9 = 1,366  is the correct order for using PEMDAS.</h3>
4 0
3 years ago
A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

5 0
2 years ago
Which angles are supplementary to AFE. Select all that apply.
marysya [2.9K]

Answer:

B and C

Step-by-step explanation:

They are on the same line so they ad up to 180 and are supplementary

7 0
2 years ago
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