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Sveta_85 [38]
3 years ago
9

FePO4 + Na2SO4  Fe2(SO4)3 + Na3PO4

Chemistry
1 answer:
lyudmila [28]3 years ago
5 0

Mass Fe₂(SO₄)₃ : 31.79 g

<h3>Further explanation</h3>

Reaction

2FePO₄ + 3Na₂SO₄ ⇒ Fe₂(SO₄)₃ + 2Na₃PO₄

mol FePO₄ (MW=150,82 g/mol) :

\tt \dfrac{24}{150.82}=0.159

mol  Fe₂(SO₄)₃ : mol FePO₄ = 1 : 2, so mol Fe₂(SO₄)₃ :

\tt \dfrac{1}{2}\times 0.159=0.0795

mass Fe₂(SO₄)₃ (MW=399,88 g/mol) :

\tt 0.0795\times 399,88 g/mol=31.79~g

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