Answer : The compartment that has the higher osmotic pressure is, 10 % (m/v) starch solution.
Explanation :
Formula used for osmotic pressure :
![\pi=\frac{nRT}{V}\\\\\pi=\frac{wRT}{MV}](https://tex.z-dn.net/?f=%5Cpi%3D%5Cfrac%7BnRT%7D%7BV%7D%5C%5C%5C%5C%5Cpi%3D%5Cfrac%7BwRT%7D%7BMV%7D)
where,
= osmotic pressure
V = volume of solution
R = solution constant = 0.0821 L.atm/mole.K
T= temperature of solution = ![25^oC=273+25=298K](https://tex.z-dn.net/?f=25%5EoC%3D273%2B25%3D298K%20%20)
M = molar mass of solute
w = mass of solute
Now we have to determine the osmotic pressure for the following solution.
<u>For 1 % (m/v) starch solution :</u>
1 % (m/v) starch solution means that 1 grams of starch present in 100 mL or 0.1 L of solution.
Molar mass of starch = 692.7 g/mol
![\pi=\frac{(1g)\times (0.0821Latm/moleK)\times (298K)}{(692.7g/mol)\times (0.1L)}](https://tex.z-dn.net/?f=%5Cpi%3D%5Cfrac%7B%281g%29%5Ctimes%20%280.0821Latm%2FmoleK%29%5Ctimes%20%28298K%29%7D%7B%28692.7g%2Fmol%29%5Ctimes%20%280.1L%29%7D)
![\pi=0.353atm](https://tex.z-dn.net/?f=%5Cpi%3D0.353atm)
<u>For 10 % (m/v) starch solution :</u>
10 % (m/v) starch solution means that 10 grams of starch present in 100 mL or 0.1 L of solution.
Molar mass of starch = 692.7 g/mol
![\pi=\frac{(10g)\times (0.0821Latm/moleK)\times (298K)}{(692.7g/mol)\times (0.1L)}](https://tex.z-dn.net/?f=%5Cpi%3D%5Cfrac%7B%2810g%29%5Ctimes%20%280.0821Latm%2FmoleK%29%5Ctimes%20%28298K%29%7D%7B%28692.7g%2Fmol%29%5Ctimes%20%280.1L%29%7D)
![\pi=3.53atm](https://tex.z-dn.net/?f=%5Cpi%3D3.53atm)
From this we conclude that, 10 % (m/v) starch solution has the higher osmotic pressure as compared to 1 % (m/v) starch solution.
Hence, the compartment that has the higher osmotic pressure is, 10 % (m/v) starch solution.