Question

2. 10 kg of food at a moisture content of 320% dry basis is dried to 50% wet basis. Calculate the amount of water removed

Answer 1

Answer:

3.6 kg of water is being removed.

Explanation:

Initial weight of food sample = 10 kg

The dry weight is 32% means it has 3.2 kg of dry mass and 6.8 kg of water.

On heating the sample becomes 50% wet basis it means the sample contains 50% dry weight. The earlier dry mass was 3.2 kg, and there will be no change in it.Thus the mass of water will also be 3.2 kg (50%).

The initial mass of water = 6.8 kg

the final mass of water =3.2 kg

The mass of water removed= 6.8 -3.2 = 3.6 kg