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4 years ago

How does heat flow in air and ocean currents

2 answers:

7 0

The transfer of heat energy within the atmosphere, hydrosphere, and the Earth's surface and interior occurs as a result of radiation, convection, and conduction. Ocean currents play a significant role in transferring this heat toward the poles.

marin [14]4 years ago

4 0

Answer:

the transfer of heat energy within the atmosphere, hydrosphere, and the earth's surface and interior occurs as a result of radiation, convection, and conduction. ocean currents play a significant role in transferring this heat toward the poles.

You might be interested in

When the products of a reaction have a lower enthalpy than the reactants___?

amid [387]

Answer:

The reactión is exothermic

Explanation:

The change in enthalpy follow the next equation:

ΔH = ΔH(products) - ΔH(reactants)

If the products have a lower enthalpy means that ΔH<0; this mean that the reaction gives heat to the environment

5 0

4 years ago

Read 2 more answers

4 Au(s) + 8 NaCN(aq) + O2(g) + 2 H2O(ℓ) → 4 NaAu(CN)2(aq) + 4 NaOH(aq) (2) 2 NaAu(CN)2(aq) + Zn(s) → 2 Au(s) +Na2[Zn(CN)4](aq) I

marysya [2.9K]

Answer:

72.57 grams

Explanation:

The mass percentage of gold in the ore is 0.19 %

The mass of ore used = 23 kg

The mass of gold in the ore = $\frac{0.19X23}{100}=0.0437kg$

moles of gold in the given mass of ore = $\frac{mass}{Atomic mass}=\frac{0.437X1000}{197}=2.22mol$

As per given equation four moles of Au is giving four moles of complex compound on reacting with NaCN

Then in second reaction two moles of the complex is reacting with one mole of Zinc

Thus two moles of gold are reacting with one mole of Zinc

The moles of Zinc needed = 0.5 X 2.22 mol = 1.11 moles

The mass of Zinc needed = moles X atomic mass =1.11 X 65.38 = 72.57 grams

6 0

3 years ago

How many moles of sodium nitrate, NaNO3, do you need to make 22.4L of oxygen gas at STP? *also if you can help with the other qu

max2010maxim [7]

<h2>Question no.18 </h2><h2>Part 1:</h2><h2>Answer:</h2>

We need 2 moles of sodium nitrate NaNO3 fro the production of one mole of oxygen gas.

<h3>Explanation:</h3>

The balanced chemical equation is:

2NaNO3 →→→→ 2NaNO2 + O2.

From the balanced chemical equation, it is obvious that for the production of One molecule of oxygen two molecules of NaNO3 breakdown.

So 22.4 L is equal to one mole.

Hence for the production of one mole of oxygen gas two moles of sodium nitrate will be needed.

<h2>Part b.</h2><h2>Answer:</h2>

The grams of NaNO3 for the production of 23.98 L of oxygen gas is 181.8786.

<h3>Explanation:</h3>

From the balanced chemical equation is:

2NaNO3 →→→→ 2NaNO2 + O2.

For the production of one mole of oxygen we need two moles of NaNO3.

So for 22. 4 L of O2 = 2 moles of NaNO3.

For:

1 L = 2/22.4

23.98 L = 2/22.4 * 23.98 = 2.14 moles.

In one mole of NaNO3, there are 84.99 grams.

So in 2.14 moles:

Mass in grams = 2.14 * 84.99 = 181.8786 g

Hence the grams of NaNO3 for the production of 23.98 L of oxygen gas is 181.8786.

<h2>Question 19</h2><h2>Part a:</h2><h2>Answer:</h2>

<u>If 48.8 L of the oxygen gas is used in the reaction then 48.8 liters of the carbon mono oxide gas will produce.</u>

<h3>Explanation:</h3>

From the balanced chemical equation:

C6H6S + 6O2 →→→→ 6CO + 3H2O + SO3

In the production of the six carbon monoxide six oxygen molecules are used up.

It means the ratio is 1 : 1.

It means the the amount of CO produced will be equal to the amount of O2 used.

So for the production of 48.8 L of carbon mono oxide production, the 48.8 L of the oxygen gas will be needed.

<h2>Part b.</h2><h2>Answer:</h2>

The 0.005648 L of the CO will produce with the use of 0.005648 L of oxygen gas.

<h3>Explanation:</h3>

From the balanced chemical equation:

C6H6S + 6O2 →→→→ 6CO + 3H2O + SO3

In the production of the six carbon mono oxide six oxygen molecules are used up.

It means the ratio is 1 : 1.

It means the the amount of CO produced will be equal to the amount of O2 used.

One mole of any gas is equal to 22.4 L.

So for the production of 0.005648 L of carbon mono oxide production, the 0.005648 L of the oxygen gas will be needed.

<h2>Part C.</h2><h2>Answer:</h2>

The 2.98 L of the carbon monoxide will be produced if we use 2.98 liters of oxygen gas.

<h3>Explanation:</h3>

From the balanced chemical equation, we can predict the amount of reactants and products in the chemical equation.

From the balanced chemical equation:

C6H6S + 6O2 →→→→ 6CO + 3H2O + SO3

In the production of the six carbon mono oxide six oxygen molecules are used up.

It means the ratio is 1 : 1.

It means the the amount of CO produced will be equal to the amount of O2 used.

One mole of any gas is equal to 22.4 L.

Hence for use of 2.97 L of oxygen gas, the 2.98 L of the carbon monoxide will be produced

7 0

3 years ago

Could someone help with this? Much appreciated!

alekssr [168]

Answer:

The 3rd answer down.

Na²O (sodium oxide) will be a base when exposed to water H²O

Explanation:

Sodium Oxide Na²O, will become Sodium Hydroxide after being exposed to water (at 80% I believe).

The oxygen ion in Na²O has 2 extra electrons which makes it highly charged and very attractive to hydrogen ions. The attraction is so strong that when Na²O comes in contact with H²O, the O(-2) strips off a hydrogen from water, forming 2 x OH ions which of course are still strongly basic.

6 0

3 years ago

What is true about the formation of a bond?

timama [110]

Answer:

There is an overall release of energy when bonds form.

Explanation:

There is a general release of energy when bonds form. This energy is called bond energy.

Bond energy is involved in the breakdown or formation of one or more bonds between atoms of a molecule. Atoms bond with each other to achieve their electronic stability, that is, they move from a higher energy situation to a lower energy one. With this we can state that when the bond between atoms is formed, energy is released; therefore, its breakdown depends on energy absorption.

3 0

4 years ago