Answer:
The probability of a person going to work by car is 48
And the probability of different way is 52
Step-by-step explanation:
As it's represented in the table above, there are 48 percent employees use cars as their transportation to work, and to find the rest sum all the probability of other transportation together which will give you 52 percent.
Answer:
Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.
Step-by-step explanation:
Given:
Population for rabbit obeys exponential law.
120 at 1990 and 240 1991 ...after 1 year time period
To Find:
After 9 year time period how many rabbits will be there.
Solution:
Exponential law goes on present value and various value and time period and defined as ,
let Y be present value Y0 previous year value and k exponential constant and t be time period.
So
Y=Y0e^(kt)
Here Y=240 ,Y0=120 t=1 year time period
So
240=120e^(k*1)
240/120=e^k
2=e^k
Now taking log on both side, [natural log]
ln(2)=ln(e^k)
ln(2)=kln(e)
k=ln(2)
k=0.6931
For t=9 year of time period
Y0=120, t=9 ,k=0.6931
Y=Y0e^(k*t)
Y=120*e^(0.6931*9)
=120e^6.2383
=61438.48
=61438 rabbits
A=10
b=2
i got my answer by doing 4*2*2*2 which is 12
Answer:
The required equation is 
.
Step-by-step explanation:
Consider the provided information.
Write a division equation that has a solution of 12.
The required division equation is shown below:
Solve the above equation a shown.
Now check this with algebraic method.
The required tape diagram is shown below:
Which is true, Hence 12 is the correct answer.
Answer:
The answer would be -7/20
Step-by-step explanation:
You have (7/15) * (-3/4)
What you have to do is multiply the numerators, 7 and -3, which is -21.
Then you multiply the denominators, 15 and 4, which is 60.
Your fraction should then look like this (-21/60). *numerator/denominator
Then you simplify them by divided both numbers by 3, which gives your answer, (-7/20).
Since 7 is prime, the fraction can no longer be simplified any more.
