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sdas [7]
3 years ago
7

If a system of linear equations has no solution, then ______.

Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0

Answer:

Answer. Answer: A system of linear equation has no solution when the graphs are parallel.Step-by-step explanation:

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I need help please aspa​
NNADVOKAT [17]

Answer:

139⁰

Step-by-step explanation:

90+49+41=180

180-41=139⁰

5 0
3 years ago
can anyone answer this ? or recommend a better website or app that’s good for doing algebra problems like these..
PSYCHO15rus [73]

Answer:

  (A)  7/(m+4)

Step-by-step explanation:

When fractions have a common denominator, you add them by adding their numerators and using that sum with the common denominator.

Here, you may be able to cancel a common factor from numerator and denominator to simplify the expression further.

  \dfrac{4m-17}{m^2-16}+\dfrac{3m-11}{m^2-16}=\dfrac{4m-17+3m-11}{m^2-16}=\dfrac{7m-28}{m^2-16}\\\\=\dfrac{7(m-4)}{(m+4)(m-4)}=\boxed{\dfrac{7}{m+4}}

5 0
2 years ago
Anybody good at geometry I need help with this worksheet
Llana [10]

Answer:

Number 1: x≈4.9412824

Number 2: x=3√10,−3√10x=310,-310

Decimal Form:

x=9.48683298...−9.48683298...

Number 3: x≈−5.04938819

Number 4: x=−1+2√6,−1−2√6x=-1+26,-1-26

Decimal Form:

x=3.89897948…,−5.89897948…

Number 5: x=−7+√93,−7−√93x=-7+93,-7-93

Decimal Form:

x=2.64365076…,−16.64365076…

Number 6: x=1+i√3910,1−i√3910

6 0
3 years ago
5a + 3b + c= 40<br> a-3b+2c= -10<br> 14a-2b+3c= 50
aalyn [17]

Answer:

a= 40-3b-c/5

a=-10+3b-2c

a=50+2b-3c/14

Step-by-step explanation:

5a+3b+c-(3b+c)=40-(3b+c)

5a=40-3b-c

5a/5=40/5-3b/5-c/5

a= 40-3b-c/5

a-3b+2c-(3b+2c)=-10-(-3b+2c)

a=-10+3b-2c

14a-2b+3c-(-2b+3c)=50-(-2b+3c)

14a=50+2b-3c

14a/14=50/14+2b/14-3c/14  

a=50+2b-3c/14

8 0
3 years ago
A line has a slope of 3 and includes the points (-10,2) and (-8,k). what is the value of g.
qwelly [4]

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-10, 2) and (-8, k) and the slope m = 3. Substitute:

\dfrac{k-2}{-8-(-10)}=3\\\\\dfrac{k-2}{2}=3\qquad\text{multiply both sides by 2}\\\\k-2=6\qquad\text{add 2 to both sides}\\\\\boxed{k=8}

4 0
4 years ago
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