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Effectus [21]
2 years ago
9

Solve the following proportion for u. 17/13=u/4

Mathematics
1 answer:
icang [17]2 years ago
5 0

Answer:

u=5.23

Step-by-step explanation:

\frac{17}{13} =\frac{u}{4}\\13u=68~by~cross-multiplication\\u=5.23~rounded~to~the~nearest~hundreds

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A recipe for salad dressing calls for 1/4 cup vinegar to 2/3 cup oil.how many cups of oil are needed for each cup of vinegar
Irina-Kira [14]
( \frac{2}{3})( \frac{4}{1}) = \frac{8}{3} cups of oil
8 0
2 years ago
Read 2 more answers
Angles A and B are located in the first quadrant such that sinA= 7/25 and cosB = 5/13. Determine the exact value for cos (A-B).
fomenos

Answer:

  204/325

Step-by-step explanation:

You can work this a couple of ways. We expect you are probably expected to use trig identities.

  cos(A) = √(1 -sin²(A)) = 24/25

  sin(B) = √(1 -cos²(B)) = 12/13

cos(A -B) = cos(A)cos(B) +sin(A)sin(B) = (24/25)(5/13) +(7/25)(12/13)

  = (24·5 +7·12)/325

cos(A -B) = 204/325

__

The other way to work this is using inverse trig functions. It is necessary to carry the full calculator precision if you want an exact answer.

  cos(A -B) = cos(arcsin(7/25) -arccos(5/13)) = cos(16.2602° -67.3801°)

  = cos(-51.1199°) ≈ 0.62769230 . . . . (last 6 digits repeating)

The denominators of 25 and 13 suggest that the desired fraction will have a denominator of 25·13 = 325, so we can multiply this value by 325 to see what we get.

  325·cos(A-B) = 204

so, the exact value is ...

  cos(A -B) = 204/325

8 0
2 years ago
I dont understand this problem ​
zzz [600]

Answer:

<em>64 ; 8</em>

Step-by-step explanation:

a² ± 2ab + b² = (a ± b)²

x² + 2(8)(x) + 8² =

x² + 16x + <em>64</em> =

(x + <em>8</em>)²

4 0
3 years ago
I don’t understand the question in the picture. Please help
Alina [70]
I believe the answer is 25.
Twenty-five is perfectly divisible by 5
If you divide it by 2,3, or 4 there is one left over.
So twenty-five is a reasonable answer
3 0
3 years ago
Pls help with my 10 gr math
Anna35 [415]

Lets review the options one by one:

X A.) The question says the y must be <u>less than</u> 100, not less than or equal to.

X B.) The y becomes 0, but 0 is neutral, not a positive number.

X C.) The height must be positive at all times, according to the range given.

√ D.) The given graph contains a max with a positive number under 100.

Therefore, the correct answer choice would be Option D (4).

<em>Hope this helps! :)</em>

4 0
2 years ago
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