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Bezzdna [24]
3 years ago
6

Hector made a scale drawing of the front of a

Mathematics
1 answer:
k0ka [10]3 years ago
5 0

Option B is correct. I did the test and it shows 100% I hope it helped!

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Please Help Will Give Brainliest
Gennadij [26K]

Answer:

1) 70 for both of them

2) Plot A's range is 100-50 = 50, Plot B's range is 100 - 40 = 60 so Plot A has the lesser range

3) Plot B's IQR is 85 - 60 = 25, Plot A's IQR is 80 - 65 = 15 so Plot B has the greater IQR

4) A: 80, B: 85

5) A: 65, B: 60

6) 50

7) 100

8) Plot B, see #2 for work

9) 50% - 50% of data is always between Q1 and Q3

10) 25%

11) 25%

8 0
3 years ago
Let (12,-5) be a point on the terminal side of an angle 0. Find the values of sin e, cose, and tan
lord [1]

Answer:

Sin = -5/13

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Step-by-step explanation:

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3 years ago
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Free_Kalibri [48]
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6 0
3 years ago
Here are summary statistics for randomly selected weights of newborn​ girls: nequals202​, x overbarequals28.3 ​hg, sequals6.1 hg
Lorico [155]

Answer:

The confidence interval is 27.5 hg less than mu less than 29.1 hg

(A) Yes, because the confidence interval limits are not similar.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = 28.3 hg

sd = 6.1 hg

n = 202

degree of freedom = n-1 = 202-1 = 201

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value corresponding to 201 degrees of freedom and 5% significance level is 1.97196

E = t×sd/√n = 1.97196×6.1/√202 = 0.8 hg

Lower limit = mean - E = 28.3 0.8 = 27.5 hg

Upper limit = mean + E = 28.3 + 0.8 = 29.1 hg

95% confidence interval is (27.5, 29.1)

When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17

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3 years ago
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Serggg [28]
I don’t that’s a question
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3 years ago
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