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3 years ago

How many people ate at least 1 banana last week? Explain your answer.

Mathematics

2 answers:

AleksAgata [21]3 years ago

7 0

I think it would be 11, because 11 people had at least one banana

Lostsunrise [7]3 years ago

6 0

Answer:

11 people ate at least 1 banana.

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(3x^4y^5) ^ 3/7 in radical form

kobusy [5.1K]

The expression in radical form is $(\sqrt[7]{3x^4y^5}) ^3$

In order to express the given indices expression in radical form, we need to ensure there is a square root present in the resulting expression.

According to the law of indices,

$a^{m/n} = \sqrt[n]{m}$

Given the indices $(3x^4y^5) ^ {3/7}$

Comparing with the general formula, we will see that:

m = 3

n = 7

a = $3x^4y^5$

Applying the law of indices:

$(3x^4y^5) ^ {3/7} = (\sqrt[7]{3x^4y^5}) ^3$

Hence the expression in radical form is $(\sqrt[7]{3x^4y^5}) ^3$

Learn more here: brainly.com/question/6755932

3 0

2 years ago

(a+b)^2 hihhhhhhhhhhhhhhhhhhhh

OverLord2011 [107]

Answer:

a^2 + 2ab + b^2

Answered by Gauthmath

3 0

3 years ago

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De dónde se obtienen los datos generales complementarios que se utilizan para calcular la razones de actividad

VARVARA [1.3K]

Answer:

En el departamento de ventas.

Explicación paso a paso:

Los datos generales complementarios se pueden obtener del departamento de ventas donde están presentes los datos sobre ventas y nos ayudan a calcular los ratios de actividad. El índice de actividad se puede calcular dividiendo las ventas de la empresa por sus activos totales. Este índice de actividad indica la eficiencia de una empresa mediante el uso de sus activos disponibles para producir ventas. El índice de actividad también se denomina "Índice de gestión de activos". Los datos de ventas son necesarios para el índice de actividad que puede estar disponible en el departamento de ventas.

8 0

3 years ago

How would the factor pairs change if nancy had only 5 posters to arrange?

Romashka [77]

Answer:

Part A) Nancy can arrange the posters in 4 ways

Part B) Nancy can arrange the posters in 2 ways

Step-by-step explanation:

<u><em>The complete question is</em></u>

Nancy has 10 movie posters. She wants to hang them on a wall in equals rows.

A) Find all the ways that she can arrange the posters.

B) How would the factor pairs change if Nancy had only 5 posters to arrange?

Part A) Find all the ways that she can arrange the posters.

we know that

The factors of 10 are

1x10 -----> 1 row of 10 posters

2x5 -----> 2 rows of 5 posters

5x2 -----> 5 rows of 2 posters

10x1 -----> 10 rows of 1 poster

therefore

Nancy can arrange the posters in 4 ways

Part B) How would the factor pairs change if Nancy had only 5 posters to arrange?

we know that

if Nancy had only 5 posters to arrange

then

The factors of 5 are

1x5 -----> 1 row of 5 posters

5x1 -----> 5 rows of 1 poster

therefore

Nancy can arrange the posters in 2 ways

3 0

3 years ago

Which is the solution to the equation below? 9=n+3

Lyrx [107]

9=n+3
Subtract 3 on each side

n=6

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3 years ago

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