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ICE Princess25 [194]
2 years ago
7

Helpppppppppppppppppp​

Mathematics
2 answers:
Wewaii [24]2 years ago
7 0

Answer:

It would be 2 1/12

Step-by-step explanation:

You would first change 1 2/3 to an improper fraction

5/3 ÷ 4/5

Then you would use Keep, Change, Flip (KCF) to get

5/3 x 5/4

Then multiply to get

25/12 then simplify to get

2 1/12

Elan Coil [88]2 years ago
3 0

Answer:

Its C lol not that hard to do

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Geometry pretty pleases
Grace [21]

Area= width times height

Perimeter= all sides added together

5 0
3 years ago
Read 2 more answers
Evaluate 9 times p when p= 3.5
zysi [14]

Answer: 31.5

Step-by-step explanation:

9*3.5=31.5

Hopefully this is what they meant

7 0
3 years ago
Without drawing the graph of the equation, determine how many points the given equation have in common with the x-axis and where
Gala2k [10]
Remark
It's asking you to complete the square to find the vertex. 

Solve
y = -2x^2 + x + 3 Put brackets around the first 2 terms.
y = (-2x^2 + x) + 3    Pull out the 2.
y = -2(x^2 - 1/2 x) + 3 Be especially observant of the sign on 1/2x Divide the middle term's number by 2 and square it. 
y = -2(x^2 - 1/2 x + [(1/2) / 2]^2 ) + 3 [1/2 divided by 2 is 1/4. (1/4)^2 = 1/16; 2*(1/16) = 1/8
y = - 2(x^2 - 1/2 x + (1/4)^2 ) + 3 + 1/8
y = -2(x - 1/4)^2 + 3 1/8

Comment
Answer to your question. The maximum value (3 1/8) is above the y axis. That means the graph of the equation crosses the x axis twice. I'm going to include the graph because in answering the question, there is no harm in seeing the graph.

4 0
3 years ago
Find the probability of rolling factors of 4.​
mylen [45]

The probability of rolling factors of 4 are 4/1 or 2/1

8 0
3 years ago
A ship leaves port on a bearing of 34.0 and travels 10.4 mi. the ship then turns due east and travels 4.6mi. how far is the ship
Natasha2012 [34]
A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)

The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi

the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles

It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°
6 0
3 years ago
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