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3 years ago

B + (4 - a) x 9 = ???

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

4 0

Answer:

-9a + b + 36

Step-by-step explanation:

lidiya [134]3 years ago

4 0

Answer:

-9a + b + 36

hope this helps

have a good day :)

Step-by-step explanation:

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What is the answer to 1 1/8 + 1 3/4 plus how you did it

I am Lyosha [343]

So instead of 3/4 we’re gonna make it easy for us and multiply the top and bottom
1+1/8+1+6/8
2+7/8
Answer: 2 7/8

6 0

2 years ago

A shirt is on sale for 20% off. The tag says that it is originally priced at $60. What is the discount on the shirt?

frez [133]

Steps:
"Of" means "x" (times)
For 20% pretend there is an imaginary decimal at the end and move that decimal all the way to the front.

Now what is .20 of (times) $60 = 12

I think that's what you wanted. The discount price

4 0

3 years ago

Use Stokes' Theorem to calculate the circulation of the field F around the curve C in the indicated direction. F = 3yi + yj+zk

jok3333 [9.3K]

Answer:

$\int \int \bigtriangledown F\ X\ dS = \int F\cdot dr$ = 12π

Step-by-step explanation:

The field F is given by:

$F = 3y\hat{i} + y\hat{j}+z\hat{k}$ (1)

The curve C is the ellipse:

$\frac{x^2}{4}+\frac{y^2}{64}=1\\\\(\frac{x}{2})^2+(\frac{y}{8})^2=1$

In order to calculate the circulation of F around the curve C, you first find the parametric equation for the given ellipse.

The general form of an ellipse equation is:

$(\frac{x}{a})^2+(\frac{y}{b})^2=1$

The parametric equation is:

$r(t)=acost \hat{i} + bsint\hat{j}=2cost\hat{i}+8sint\hat{j}$ (2)

The Stokes's theorem is given by the following identity:

$\int \int \bigtriangledown F\ X\ dS = \int F\cdot dr$

The path integral is also:

$\int F\cdot dr=\int F(r(t))\cdot dr(t)$ (3)

For F(r(t)) and dr(t) you obtain:

$F(r(t))=3(8sint)\hat{j}+(8sint)\hat{j}+(z)\hat{k}\\\\dr(t)=(-2sint\hat{i}+8cost\hat{j}+0\hat{k})dt\\\\F(r(t))\cdot dr(t)=(-48sin^2t+64cos^2t)dt$

Next, in the equation (3) you obtain:

$\int_0^{2\pi} (-48sin^2t+64cos^2t)dt=\int_0^{2\pi}(-\frac{48}{2}(1-cos2t)+\frac{64}{2}(1+cos2t))dt\\\\=\int_0^{2\pi}(-24+24cos2t+32+32cos2t)dt\\\\=\int_0^{2\pi}(6+56cos2t)dt\\\\=[6t+56sin2t]_0^{2\pi}=[6(2\pi)-0]=12\pi$

The circulation of the field around C is 12π

5 0

3 years ago

Solve for x: three fourths times x plus five fourths equals four times x

Nostrana [21]

Answer:

x equals five thirteenths

Step-by-step explanation:

To solve this, we will follow the steps below;

$\frac{3}{4}$ × x + $\frac{5}{4}$ = 4 × x

$\frac{3x}{4}$ + $\frac{5}{4}$ = 4x

$\frac{3x + 5}{4}$ = 4x

Multiply both-side of the equation by 4

$\frac{3x + 5}{4}$ × 4= 4x × 4

On the left-hand side of the equation 4 will cancel-out 4, thus the equation becomes;

3x + 5 = 16x

subtract 3x from both-side of the equation

16x - 3x = 5

13x = 5

Divide both-side of the equation by 13

$\frac{13x}{13}$ = $\frac{5}{13}$

(On the left-hand side of the equation 13 at the numerator will cancel-out 13 at the denominator while on the right-hand side of the equation 5 will be divided by 13)

x = $\frac{5}{13}$

x equals five thirteenths

7 0

3 years ago

I need help on this. Can someone explain it?

kozerog [31]

Answer:

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5 0

3 years ago

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