Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:
-15
Step-by-step explanation:
start from the inside and go out.
So first plug in -3 into g(x)
g(-3) = -3 - 7 = -10
then plug in -10 into f(x)
f(-10) = 2(-10) + 5 = -15
so f(g(x)) = -15
A = 180
b = 180
c = 180
180+180-180 = 180
0.4 is the answer, 3/5= 0.6
Answer:
8
Step-by-step explanation:
that;'s what i put the first time
