Answer:
Ans1.
double calc_a;
calc_a=Math.pow(3.0,2.0)+Math.sqrt(9);
Ans2.
double calc_b;
calc_b=((12.0/3.0)-(2.0*4.0));
Ans 3.
double calc_c;
calc_c=(Math.sqrt(16.0)*(7.0+9.0));
Ans 4.
double calc_d;
calc_d=Math.pow(7.0,2.0)/Math.sqrt(49.0);
Explanation:
The expressions are done with Java in answer above.
<h2>• Father=Charles Babbage</h2>
<h2>• Mother=Ada Lovelace</h2>

Answer:
The code to this question can be given as:
Code:
public class Book //define class.
{
private String title, author; //define variable.
Book(String a, String b) //define parameterized constructor.
{
title = a; //holding value.
author = b;
}
public String toString() //string function
{
return title + "\n" + author; //return value.
}
}
Explanation:
In the above java code firstly we declare the class book that name is already given in the question. Then we declare the private variable that datatype is string author and title. Then we declare the parameterized constructor. In the parameterized constructor we use the private variable for hold constructor parameter value. Then we declare the tostring() function in this function we return value of the title and author variable.
Answer:
#include <iostream>
#include <cstring>
using namespace std;
bool isAPalindrome(char* palindrome);
int main()
{
char palindrome[30];
bool palindrome_check;
cout << "Please enter an word or phrase.\n";
cin.getline(palindrome, 30);
palindrome_check = isAPalindrome(palindrome);
if (palindrome_check = true)
{
cout << "Input is a palindrome\n";
}
else
{
cout << "Inputis not a palindrome\n;";
}
system("pause");
return 0;
}
bool isAPalindrome(char* palindrome)
{
char* front;
char* rear;
front = palindrome;// starts at the left side of the c string
rear = (palindrome + strlen(palindrome)) - 1;//starts at the right side of the c-string. adds the c string plus the incriment value of s
while (front <= rear)
{
if (front = rear)
{
front++;
rear--;
}
else
{
return false;
}
}
return true;
}
Hello there!
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I hope this helps!
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