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Degger [83]
3 years ago
9

A decade-old study found that the proportion of high school seniors who felt that "getting rich" was an important personal goal

was . Suppose that we have reason to believe that this proportion has changed, and we wish to carry out a hypothesis test to see if our belief can be supported. State the null hypothesis and the alternative hypothesis that we would use for this test.
Mathematics
1 answer:
Tasya [4]3 years ago
6 0

Answer:

Construction of hypothesis

H₀ : p = 0.70

H₁ : p ≠ 0.70

Step-by-step explanation:

A the given statement does not give how much the goal was

lets suppose "getting rich" was an important personal goal than the proportion was 70 %

suppose that we believe that proportion has changed then construction of hypothesis for this H₀  for null hypothesis and H₁ is alternative hypothesis

Construction of hypothesis

H₀ : p = 0.70

H₁ : p ≠ 0.70

So construction of hypothesis state null and alternative hypothesis.

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What is the slope-intercept form of them equation of a line that passes through (5, -4) and has a slope of 3/4?
EastWind [94]

C is correct answer, passes through (5,-1) and also has slope of 3/4



5 0
3 years ago
What is the solution of the system? Use elimination. <br><br> 5x-6y=-32<br> 3x+6y=48
vampirchik [111]

Answer:

x=2 y=7

Step-by-step explanation:

Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

7 0
2 years ago
Read 2 more answers
Let Ebe the set of all even positive integers in the universe Zof integers, and XE : Z R be the characteristic function of E.
AnnZ [28]

Answer:

\mathbf{X_E (2) =  1}

\mathbf{X_E (-2) = 0 }  

\mathbf{\{ x \in Z: X_E(x) = 1\}  = E}

Step-by-step explanation:

Let E be the set of all even positive integers in the universe Z of integers,

i.e

E = {2,4,6,8,10 ....∞}

X_E : Z \to R be the characteristic function of E.

∴

X_E(x) = \left \{ {{1 \ if  \ x \ \  is \ an \ element \ of \ E} \atop {0 \ if  \ x \ \  is \ not \ an  \ element \ of \ E}} \right.

For XE(2)

\mathbf{X_E (2) =  1}  since x is an element of E (i.e the set of all even numbers)

For XE(-2)

\mathbf{X_E (-2) = 0 }   since  - 2 is less than 0 , and -2 is not an element of E

For { x ∈ Z: XE(x) = 1}

This can be read as:

x which is and element of Z such that X is also an element of x which is equal to 1.

∴

\{ x \in Z: X_E(x) = 1\} = \{ x \in Z | x \in E\} \\ \\  \mathbf{\{ x \in Z: X_E(x) = 1\}  = E}

E = {2,4,6,8,10 ....∞}

5 0
3 years ago
50*50+60+90+40-60-43-89-30-34+12​
tensa zangetsu [6.8K]
The answer is 2446.
5 0
3 years ago
Read 2 more answers
8-2|4-5y|=4<br><br> | | stands for absolute value
Contact [7]

Answer:

y = (2/5) OR y = (6/5)

Step-by-step explanation:

The first step is isolating the expression within the absolute value bars. The first thing we can do is subtract both sides by 8. If we do that, we get -2|4-5y| = -4. Now, to completely isolate the absolute value, we would have to divide by -2. This yields |4 - 5y| = 2. Finally, we can remove the absolute value bars. However, to do this, we need to first understand what an absolute value bar does to an equation. Lets say that |x| = 2. Absolute value describes the DISTANCE of some quantity from 0 (on the number line). Therefore, x (which is inside the absolute value bars) can be either positive or negative 2 (they are BOTH two units away from 0). Similarly, in this case, (4 - 5y) can either be 2 or -2 (because the absolute value of both is 2). Now we have two possible solutions to solve for:

4 - 5y = 2 OR 4 - 5y = -2

5y = 2 OR 5y = 6

y = (2/5) OR y = (6/5)

If we plug both of these answers back into the equation we can see that they both check out.

4 0
2 years ago
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