I’m pretty sure you just do 11-4 and get 7 and then do like 99 divided by 7?
Answer:
-14x^4+4x^3-6xy^3
Step-by-step explanation:
Answer:
x = 12
Step-by-step explanation:
The product of the length of the secant segment and its external part equals the square of the length of the tangent segment.
3*x = 6^2
3x = 36
Divide each side by 3
3x/3 = 36/3
x = 12
Answer:
6x-4
Step-by-step explanation:
Let's simplify step-by-step.
2(3x−2)−(4x−4x)
Distribute the Negative Sign:
=2(3x−2)+−1(4x−4x)
=2(3x−2)+−1(4x)+−1(−4x)
=2(3x−2)+−4x+4x
Distribute:
=(2)(3x)+(2)(−2)+−4x+4x
=6x+−4+−4x+4x
Combine Like Terms:
=6x+−4+−4x+4x
=(6x+−4x+4x)+(−4)
=6x+−4
Answer:
=6x−4
The difference in the weight of the soil and compost Greg combined is 17kg.
This is because x+(3x+2)+x/2=29
2x+2(3x+2)+x=58
2x+6x+4+x=58
9x+4=58
9x=58-4
9x=54
x=6
So the weight of the fertilizer is 6kg. So the weight of the soil is 3x+2=3*6+2=18+2=20kg.
20-3=17kg
Hope it helps!
