Need help plz and thank u

A. 5 b. 7 c. 9 d. 11 PLEASE HELPPP I WILL GIVE BRILLIANT!!!

antiseptic1488 [7]

Answer:

B : 7

Step-by-step explanation:

4 0

3 years ago

Find the equation of a line passing through the point(-3,0) and (2,-3)

Svetradugi [14.3K]

Answer (assuming the question allows it to be written in slope-intercept form):

$y = -\frac{3}{5} x-\frac{9}{5}$

Step-by-step explanation:

1) First, find the slope of the equation. Use the slope formula $m = \frac{y_2-y_1}{x_2-x_1}$ , substitute the given points' x and y values, and simplify:

$m = \frac{(-3)-(0)}{(2)-(-3)} \\m =\frac{-3-0}{2+3}\\m = -\frac{3}{5}$

Thus, the slope is $-\frac{3}{5}$ .

2) Now, use the point-slope formula $y-y_1 = m (x-x_1)$ and substitute real values for $m$ , $x_1$ , and $y_1$ .

Since $m$ represents the slope, substitute $-\frac{3}{5}$ in its place. Since $x_1$ and $y_1$ represent the x and y values of a point the line crosses, use the x and y values of any one of the given points to substitute into the formula. (Either one is fine. I chose (2,-3).) Then, isolate y to put it into slope-intercept form and find the answer:

$y-(-3) = -\frac{3}{5} (x-(2))\\y + 3 = -\frac{3}{5} x + \frac{6}{5} \\y = -\frac{3}{5} x - \frac{9}{5}$

5 0

3 years ago

Read 2 more answers

Evaluate this expression if x = -4, y = 5, and z = -13. x - (-z)

LiRa [457]

Answer:

-17

Step-by-step explanation:

x - (-z)

Subtracting a negative is like adding

x+z

x = -4 and z = -13

-4 + -13

-17

8 0

3 years ago

Read 2 more answers

If we have 35 x 89 what well that make?

natali 33 [55]

Answer:

Step-by-step explanation:

3115

4 0

4 years ago

Read 2 more answers

The number of hours of daylight measured in one year in Ellenville can be modeled by a sinusoidal function. During 2006, (not a

Kamila [148]

Answer:

$f ( t ) = 3.7*sin ( 0.01736*t ) + 12$

Step-by-step explanation:

Solution:-

- We are to model a sinusoidal function for the number of hours of daylight measured in one year in Ellenville.

- We will express a general form of a sinusoidal function [ f ( t ) ] as follows:

$f ( t ) = A*sin ( w*t ) + c$

Where,

A: The amplitude of the hours of daylight

w: The angular frequency of occurring event

c: The mean hours of daylight

t: The time taken from reference ( days )

- We are given that the longest day [ $f ( t_m_a_x )$ ] occurred on June 21st and the shortest day [ $f ( t_m_i_n )$ ] on December 21st.

- The mean hours of daylight ( c ) is the average of the maximum and minimum hours of daylight as follows:

$c = \frac{f(t_m_a_x ) +f(t_m_i_n ) }{2} \\\\c = \frac{15.7 + 8.3}{2} = \frac{24}{2} \\\\c = 12$

- The amplitude ( A ) of the sinusoidal function is given by the difference of either maximum or minimum value of the function from the mean value ( c ):

$A = f ( t_m_a_x ) - c\\\\A = 15.7 - 12\\\\A = 3.7$

- The frequency of occurrence ( w ) is defined by the periodicity of the function. In other words how frequently does two maximum hours of daylight occur or how frequently does two minimum hours of daylight occur.

- The time period ( T ) is the time taken between two successive maximum duration of daylight hours. We were given the longest day occurred on June 21st and the shortest day occurred on December 21st. The number of days between the longest and shortest day will correspond to half of the time period ( 0.5*T ):

$0.5*T = 7 + 31 + 31 + 30 +31 +30 +21\\\\T = 2* [ 181 ] \\\\T = 362 days$

- The angular frequency ( w ) is then defined as:

$w = \frac{2\pi }{T} = \frac{2\pi }{362} \\\\w = 0.01736$

- We will now express the model for the duration of daylight each day as function of each day:

$f ( t ) = 3.7*sin ( 0.01736*t ) + 12$

8 0

4 years ago