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2 years ago

Write a value in each region that makes the inequality or inequalities true. 2x-1>3 and 3(x-3)<0

Mathematics

1 answer:

mixer [17]2 years ago

7 0

Answer:

Region 1 : 3

Region 2: 2

Step-by-step explanation:

Given the inequalities :

2x - 1 > 3 and 3(x-3)<0

To obtain a value inneachbregionwhicj makes the inequality or inequalities true, we solve for x

Inequality 1 :

2x - 1 > 3

Add 1 to both sides

2x - 1 + 1 > 3 + 1

2x > 4

Divide both sides by 2

2x/2 > 4/2

x > 2

(3, 4,..)

Inequality 2:

3(x-3)<0

3x - 9 < 0

Add 9 to both sides

3x - 9 + 9 < 0 + 9

3x < 9

Divide both sides by 3

3x/3 < 9/3

x < 3

(2, 1,,)

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3 years ago

What is the answer to 80

aniked [119]

10×8 is that what you mean

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3 years ago

Plz answer this fast fast I will give brainlist and 12 points

Firlakuza [10]

Answer:

a) 115°

b) 140°

c) 75°

d) 255°

Step-by-step explanation:

a) another line parallel to AB through E will split x into two sectors.

Parallel lines intersected by a third line makes opposite internal angles of equal value. Supplemental angles add to 180°

x = (180 - 120) + (180 - 125) = 115°

b) double application of parallel lines intersected by a third line making corresponding angles identical.

c) more of the same

d) more of the same

7 0

3 years ago

According to an article, 47% of adults have experienced a breakup at least once during the last 10 years. Of 9 randomly select

In-s [12.5K]

Answer:

a) $P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

b) $P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033$

And replacing we got:

$P(X \geq 1)= 1-P(X$

c) $P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257$

$P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

$P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135$

And adding we got:

$P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=9, p=0.47)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Assuming the following questions:

a. exactly five

For this case we can use the probability mass function and we got:

$P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

b. at least one

For this case we want this probability:

$P(X \geq 1)$

And we can use the complement rule and we got:

$P(X \geq 1)= 1-P(X$

$P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033$

And replacing we got:

$P(X \geq 1)= 1-P(X$

c. between four and six, inclusive.

For this case we want this probability:

$P(4 \leq X \leq 6)$

$P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257$

$P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

$P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135$

And adding we got:

$P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620$

6 0

3 years ago

In right △ABC with right angle B, m∠A=(3x−8)° and m∠C=(x−2)°.

julsineya [31]

Answer:

<A = 67

Step-by-step explanation:

The three angles of a triangle add up to 180 degrees. We know a right angle is 90 degrees.

<A + <B + <C = 180

3x-8 + 90 + x-2 =180

Combine like terms

4x-10+90 = 180

4x+80 =180

Subtract 80 from each side

4x+80-80=180-80

4x=100

Divide each side by 4

4x/4 = 100/4

x=25

But we want to know <A

<A = 3x-8

Substitute x=25

=3(25) -8

=75-8

= 67

6 0

3 years ago

Read 2 more answers