All categories

3 years ago

Answer my question please!! i will give brainlest!

Mathematics

2 answers:

Virty [35]3 years ago

6 0

Answer:

Try 27 and 37

37 for drama club

27 for yearbook club

viktelen [127]3 years ago

5 0

Hello,

Students in a drama club + in a yearbook club : 64

Students in a drama club : 10 more students than the yearbook club

Let x be the number of students in a drama club and y the number of students in the yearbook club.

We have :

x = y + 10 ⇔ x = 27 + 10 = 37

x + y = 64 ⇔ y + 10 + y = 64 ⇔ 2y = 54 ⇔ y = 27

There are 37 students in the drama club and 27 students in the yearbook club.

:-)

You might be interested in

Help me with this question please

Gala2k [10]

The answer is C
Hope this helped

3 0

3 years ago

Read 2 more answers

What is the area of the given circle in terms of pi

ser-zykov [4K]

3.14(3.3)(3.3)
3.13(10.89)

6 0

2 years ago

What is the length of the base if the area is 32 cmand the height is 4 cm

vovikov84 [41]

Answer:

128,8,28,36

Step-by-step explanation:

if u multiply 32 times 4 u get 128 but if u subtract them u get 28

but if u divide them then u get 8 but if u also add them u get 36

7 0

2 years ago

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

6 0

3 years ago

Express each of the following numbers as a power of two (2^3)^4 4*4*4*4*4

enot [183]

Answer:

2^12

2^10

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

6 0

2 years ago

Read 2 more answers