8z=4(2z+1) show step by step

1 answer:

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8z=4(2z+1)
First you would distribute the constant into the numbers in the parentheses. so
8z=8z+4
then you would combine like terms which in this case would result in a zero.
8z-8z=0 So the z would be zero or no solution.

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Hello Guys, I really need help with these questions. Here they are.

Slav-nsk [51]

Answer:

See below.

Step-by-step explanation:

It can really help to think when you see |expression| that it means the distance from expression to zero.

(a) |x| < 7 means the distance from x to 0 is less than 7. That puts x between -7 and 7. The solution set is -7 < x < 7.

(b) |x + 3| < 9 means that the distance from x + 3 to 0 is less than 9. That puts x + 3 between -9 and 9:

-9 < x + 3 < 9 Now subtract 3 from all three parts.

-12 < x < 6

(c) |y - 8| > 11 means that the distance from y - 8 to 0 is more than 11 units. That puts y - 8 in one of two places: left of -11 or right of 11.

$y-8 < -11 \text{ or } y-8 > 11\\\\y < -3 \text{ or } y > 19$

(g) $|3x-1| \ge 18$ means that the distance from 3x - 1 to 0 is more than (or equal to) 18. Another way to say it is, 3x - 1 is farther from 0 than 18 units. That puts 3x - 1 in one of two places: to the left of -18 or to the right of 18.