3 years ago

8z=4(2z+1) show step by step

1 answer:

5 0

8z=4(2z+1)
First you would distribute the constant into the numbers in the parentheses. so
8z=8z+4
then you would combine like terms which in this case would result in a zero.
8z-8z=0 So the z would be zero or no solution.

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