All categories

2 years ago

Please Help. Will mark brainliest!!!

Mathematics

1 answer:

Tanzania [10]2 years ago

6 0

Answer:

A) 3.6 miles per hour B) 1.44 miles in the last 24 minutes

Step-by-step explanation:

divide 8.64 by 2.4 to get 3.6 to find the mph then divide 3.6 by 60 to get 0.06 to find the miles per minute, then multiply 0.06 by 24 to get 1.44 miles

You might be interested in

Line j: y = 1/4x + 4

Sergio039 [100]

A.) Lines J and k because parallel lines have the same slope but NOT y-intercept.

8 0

3 years ago

Read 2 more answers

Find the compound interest on 800 at 5% per annum for 2 years.

Ludmilka [50]

Answer:

$C = 82$

Step-by-step explanation:

Given

$R = 5\%$ -- Rate

$P = 800$ -- Principal

$N = 2$ -- Time

Required

Determine the compound interest

First, we calculate the Amount (A)

$A = P(1 + R)^N$

$A = 800*(1 + 5\%)^2$

Express % as decimal

$A = 800*(1 + 0.05)^2$

$A = 800*(1.05)^2$

$A = 882$

The compound interest (C) is then calculated as:

$C = A -P$ i.e. Amount - Principal

$C = 882 - 800$

$C = 82$

7 0

2 years ago

HELP ME ASAP PLEASEEEEEEE

Vlad [161]

Answer: a) about 450

Step-by-step explanation:

50 multiplied by 9 is 450 and its asking for an approximate so it would be anything near 450

3 0

2 years ago

The circumference of a circle is 19π m. What is the area, in square meters? Express your answer in terms of \piπ.

lianna [129]

Answer:

90.25π

Step-by-step explanation:

The circumference of circle is 2πr, or in other words the diameter times π.

The area of a circle is πr^2.

19π is the circumference of this circle.

So, 19 is the diameter, and 9.5 the radius.

The area if (9.5^2)π.

9.5^2=90.25

So, in terms of π, the area of the circle is 90.25π.

7 0

2 years ago

Find the volumes of the solids generated by revolving the triangle with vertices (2, 2), (2, 6), and (5, 6) about a) the x-a

Vesna [10]

About the $x$ -axis (washer method):

$\displaystyle\pi\int_2^5\left(6^2-\left(\frac43x-\frac23\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(20+x-x^2)\,\mathrm dx=\boxed{56\pi}$

About the $y$ -axis (shell method):

$\displaystyle2\pi\int_2^5x\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5x(5-x)\,\mathrm dx=\boxed{36\pi}$

About $x=7$ (shell method):

$\displaystyle2\pi\int_2^5(7-x)\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5(35-12x+x^2)\,\mathrm dx=\boxed{48\pi}$

About $y=2$ (washer method):

$\displaystyle\pi\int_2^5\left((6-2)^2-\left(\frac43x-\frac23-2\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(5+4x-x^2)\,\mathrm dx=\boxed{32\pi}$

7 0

3 years ago