Hey there :)
Now lets name each house
A B C D E F
500ft <-> 500ft <-> 500ft <-> 500ft <-> 500ft <-> 2000ft
Let's say the bus stops at A
= 0 ( from A ) + 500 ( from B ) + 500 + 500 ( from C ) + 500 + 500 + 500 ( from D ) + 500 + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 500 + 2000 ( from F )
= 0 + 500 + 1000 + 1500 + 2000 + 4000
= 9000 ft
at B
= 500 ( from A ) + 0 ( from B ) + 500 ( from C ) + 500 + 500 ( from D ) + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 2000 ( from F )
= 500 + 0 + 500 + 1000 + 1500 + 3500
= 7000 ft
at C
= 500 ( from A ) + 500 + 500 ( from B ) + 0 ( from C ) + 500 ( from D ) + 500 + 500 ( from E ) + 500 + 500 + 2000 ( from F )
= 500 + 1000 + 0 + 500 + 1000 + 3000
= 6000 ft
Do the same for D , E and F
at D
= 6000 ft
at E
= 7000 ft
at F
= 15000 ft
You will find that the bus should stop at either C or D to make the sum of distances from every house to the stop as small as possible.
20000000+ 4000000+ 80000+ 4000+ 100+ 60+ 3
Answer:
she should cut them into thirds
Step-by-step explanation:
there are 10 oranges while there are 15 players.
a) if she cuts them into halves, she will have 20 slices with 5 left over, who will get an extra slice while who doesn't? it can't work
b) if she cuts them into thirds, she will have 30 slices with 15 left over, that is enough to give each player two slices with none left over, it works!!
c) if she cuts them into quarters, she would have 40 slices with 25 left over. this means some players would get three slices, while others would only get two. it doesn't work.
this is why B is the right answer
Answer: 41.58$
Step-by-step explanation:
