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3 years ago

6

The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 fe

et, the area will remain the same. Find the dimensions of the original rectangle.

2 answers:

alexgriva [62]3 years ago

5 0

Let the width be x.

Length is 8 feet more than width. Length = x + 8

Area = x(x + 8)

width increased by 4, that is, (x + 4)
Length decreased by 5, (x + 8 - 5) = (x + 3)

Area = (x + 4)(x +3)

Area remains the same

x(x + 8) = (x+4)(x +3)

x² + 8x = x(x +3) + 4(x +3)

x² + 8x = x² +3x + 4x +12

x² + 8x = x² +7x +12 Eliminate x² from both sides

8x = 7x + 12

8x - 7x = 12

x = 12

Dimensions of original rectangle : x, x + 8

12, 12 +8 = 12, 20

Original rectangle is 20 feet by 12 feet

kodGreya [7K]3 years ago

4 0

Answer:

12 feet by 20 feet

Step-by-step explanation:

Area = (x+4)(x+3)

x=12

x+8 = 12+8 = 20

Original triangle is 12feet by 20 feet

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