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JulijaS [17]
3 years ago
11

PLS HELPPPP ITS PROB EASY BUT I HAVE SO MANY LATE WORK TO DO:)))

Mathematics
1 answer:
kumpel [21]3 years ago
4 0

Answer:

It’s C

Step-by-step explanation:

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Describe the location of the point having the following coordinates. negative abscissa, zero ordinate between Quadrant II and Qu
Marianna [84]

Answer:

The location of the point is between Quadrant II and Quadrant III

Step-by-step explanation:

we know that

The abscissa refers to the x-axis  and ordinate refers to the y-axis

so

in this problem we have

the coordinates of the point are (-x,0)

see the attached figure to better understand the problem

The location of the point is between Quadrant II and Quadrant III

6 0
3 years ago
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professor190 [17]

Answer:

binomial

Step-by-step explanation:

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2 years ago
Write the equation of a quadratic function who has the vertex of (4,-7)
timama [110]

Given:

The vertex of a quadratic function is (4,-7).

To find:

The equation of the quadratic function.

Solution:

The vertex form of a quadratic function is:

y=a(x-h)^2+k          ...(i)

Where a is a constant and (h,k) is vertex.

The vertex is at point (4,-7).

Putting h=4 and k=-7 in (i), we get

y=a(x-4)^2+(-7)

y=a(x-4)^2-7

The required equation of the quadratic function is y=a(x-4)^2-7 where, a is a constant.

Putting a=1, we get

y=(1)(x-4)^2-7

y=(x^2-8x+16)-7             [\because (a-b)^2=a^2-2ab+b^2]

y=x^2-8x+9

Therefore, the required quadratic function is y=x^2-8x+9.

6 0
2 years ago
What info is required
7nadin3 [17]

Answer:

Z=D

Step-by-step explanation:

only included angle for AAS

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3 years ago
I WILL GIVE BRAINLIEST PLEASE HELP
irina1246 [14]

Answer:

Part I

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Part II

  • Period is 6 months, so 2 periods in a year and 2*8 = 16 periods in 8 years

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Part IV

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3 years ago
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