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Luba_88 [7]
3 years ago
7

What are the end products of anaerobic respiration in yeast cell ?​

Chemistry
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer:

glucose ethanol and co2

please follow me and mark it brainliest

SVEN [57.7K]3 years ago
7 0

Answer:

In anaerobic respiration yeast breaks down glucose, forming ethanol and carbon dioxide as its waste products. When the glucose is nearly used up, and provided that oxygen is present, yeast uses the ethanol as a respiratory substrate to produce carbon dioxide and water in aerobic respiration.

Explanation:

Hope it is helpful....

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2.568%20%5Ctimes%205.8%7D%7B4.186%7D%20" id="TexFormula1" title=" \frac{2.568 \ti
melomori [17]
Using a calculator:

(2.568 x 5.8)/4.186 = 3.5581460…
= 3.56 (3sf)

You didn’t specify the correct number of significant figures needed.
3 0
3 years ago
What is the percent mass of 55.0g NH4Cl dissolved in 137g water?
3241004551 [841]

Step 1

% by mass:

Mass of solute ---- 100 of solution

Mass of solution = mass of solute + mass of solvent = 55.0 g + 137 g = 192 g

Solute = NH4Cl

Solvent = Water (H2O)

-----------------------------

Step 2

Procedure:

55.0 g NH4Cl --------- 192 g solution

X ---------- 100 g solution

X = 29 g NH4Cl = 29 % by mass approx.

Answer: 29 % by mass

6 0
1 year ago
This is how fluorine appears in the periodic table.
IgorC [24]

Answer:

A: the atomic number

C: the number of protons

D: the number of electrons

8 0
4 years ago
Read 2 more answers
Starting with 9.3 moles of O2, how many moles of H2S will be needed and how many moles of SO2 will be produced in the following
tensa zangetsu [6.8K]

<u>Answer:</u> The amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles

<u>Explanation:</u>

We are given:

Moles of oxygen gas = 9.3 moles

The chemical equation for the reaction of oxygen gas and hydrogen sulfide follows:

2H_2S+3O_2\rightarrow 2SO_2+2H_2O

<u>For hydrogen sulfide:</u>

By Stoichiometry of the reaction:

3 moles of oxygen gas reacts with 2 moles of hydrogen sulfide

So, 9.3 moles of oxygen gas will react with = \frac{2}{3}\times 9.3=6.2mol of hydrogen sulfide

<u>For sulfur dioxide:</u>

By Stoichiometry of the reaction:

3 moles of oxygen gas produces 2 moles of sulfur dioxide

So, 9.3 moles of oxygen gas will produce = \frac{2}{3}\times 9.3=6.2mol of sulfur dioxide

Hence, the amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles

7 0
3 years ago
The atoms of a solid aluminum can are close together, vibrating in a rigid structure. if the can is warmed up on a hot plate,
Alexxx [7]

Answer:the atoms of a solid aluminium can are close together vibrating in a rigid structure if the can is warmed up on a hot plate

Explanation:

8 0
4 years ago
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