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2 years ago

If 25.0 g NO are produced, how many grams of nitrogen gas are used?

1 answer:

8 0

Using the stoichiometry of the reaction and the information provided in the question, the mass of N2 used is 11.62 g.

<h3>Chemical reaction</h3>

The term chemical reaction refers to the combiantion of two or substances to yiled one or more products. The reaction equation in this case is N2 + O2 --->2NO.

Now;

Number of moles of NO = 25g/30 g/mol = 0.83 moles

1 mole of N2 yields 2 moles of NO

x moles of N2 yileds 0.83 moles of NO

x = 0.415 moles

Mass of N2 = 0.415 moles * 28 g/mol = 11.62 g

Learn more about stoichiometry:

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How many atoms are in 6.3 moles of lead

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Answer:

3.79 x 10²⁴atoms

Explanation:

Given parameters:

Number moles of lead = 6.3moles

Unknown:

Number of atoms = ?

Solution:

To solve this problem,

1 mole of a substance contains 6.02 x 10²³ atoms

6.3 mole of Pb will contain 6.3 x 6.02 x 10²³ = 3.79 x 10²⁴atoms

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3 years ago

A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h

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Explanation:

First, calculate the moles of $CO_{2}$ using ideal gas equation as follows.

PV = nRT

or, n = $\frac{PV}{RT}$

= $\frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}$ (as 1 bar = 1 atm (approx))

= 0.183 mol

As, Density = $\frac{mass}{volume}$

Hence, mass of water will be as follows.

Density = $\frac{mass}{volume}$

0.998 g/ml = $\frac{mass}{3.26 ml}$

mass = 3.25 g

Similarly, calculate the moles of water as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{3.25 g}{18.02 g/mol}$

= 0.180 mol

Moles of hydrogen = $0.180 \times 2$ = 0.36 mol

Now, mass of carbon will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.183 mol = $\frac{mass}{12 g/mol}$

= 2.19 g

Therefore, mass of oxygen will be as follows.

Mass of O = mass of sample - (mass of C + mass of H)

= 3.50 g - (2.19 g + 0.36 g)

= 0.95 g

Therefore, moles of oxygen will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.95 g}{16 g/mol}$

= 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

C H O

No. of moles: 0.183 0.36 0.059

On dividing: 3.1 6.1 1

Therefore, empirical formula of the given compound is $C_{3}H_{6}O$ .

Thus, we can conclude that empirical formula of the given compound is $C_{3}H_{6}O$ .

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3 years ago

Why are many chemical names so complex?

Setler [38]

Answer:

cause they like it that way

Explanation:

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3 years ago

How many grams are in 2.12 x 10-2 moles of calcium phosphate, Ca3(PO3)2?

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Answer:19.2

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3 years ago

A biochemist carefully measures the molarity of magnesium ion in 47, mL of cell growth medium to be 97. ??. Unfortunately, a car

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Complete Question

The complete question is shown on the first uploaded image

Answer:

Answer: 760 uM

Explanation:

the addition of solvent to a solution in a such away that the volume of the solution increases and the concentration decreases is a process know as dilution

The concentration and the volume of the dilute and concentrated solution are given below as follows

$C_{1}V_{1}$ $= C_{f}V_{f}$

Concentrated solution Dilute solution

Given that M1 = 97.0uM

V1 = 47.0 mL

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M2 = ?

Therefore M1V1 = M2V2

M2 = M1V1/V2

M2 = (97*47)/6

M2 = 760 uM

Answer: 760 uM

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