Let's prove each one:
A) y=x-3
x=0→y=0-3→y=-3=-3 ok
x=2→y=2-3→y=-1 different to 5 No

B) y=x+3
x=0→y=0+3→y=3 different to -3 No

C) y=4x-3
x=0→y=4(0)-3=0-3→y=-3=-3 ok
x=2→y=4(2)-3=8-3→y=5=5 ok
x=3→y=4(3)-3=12-3→y=9=9 ok
x=4→y=4(4)-3=16-3→y=13=13 ok

D) y=4x+3
x=0→y=4(0)+3=0+3→y=3 different to -3 No

Answer: Option C) y=4x-3

8 0

3 years ago

What is the value of x in the equation 2x + 3y = 6 ?

erastovalidia [21]

Answer:

x = -3/2y + 3

Step-by-step explanation:

2x + 3y = 6

2x = -3y + 6

x = -3/2y + 3

3 0

3 years ago

Write 9x-3y=-69 x − 3 y = − 6 in slope-intercept form. Make sure you show all steps and inverse operations.Write 9x-3y=-69 x − 3

Goryan [66]

Answer:

y = 3x + 23 and

$y = \frac{1}{3}x + 2$

Step-by-step explanation:

The first equation is 9x - 3y = - 69 and we have to write it in slope-intercept form.

Now, 9x - 3y = - 69

⇒ 3x - y = - 23 {Dividing both sides by 3}

⇒ 3x + 23 = y

⇒ y = 3x + 23 {Interchanging the sides} (Answer)

The second equation is x - 3y = - 6 and we have to write it in slope-intercept form.

Now, x - 3y = - 6

⇒ x + 6 = 3y

⇒ 3y = x + 6 {Interchanging the sides}

⇒ $y = \frac{1}{3}(x + 6)$ {Dividing both sides by 3}

⇒ $y = \frac{1}{3}x + 2$ (Answer)

3 0

3 years ago

￼help with this please

help with this please