Answer:
-27.26 ----------- -52.89 - (-25.63)
135.03 ----------- 49.40 - (-85.63)
-120(2)/(3) ----------- -96(2)/(9) - 24(4)/(9)
-15(3)/(5) ----------- -18(1)/(5) - [-2(3)/(5)]
The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
Answer:
add up c
Step-by-step explanation:
Answer:
s = ![\sqrt[3]{999} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B999%7D%20%7D)
Step-by-step explanation:
V = s^3
Plug in the given volume.
999 = s^3
Take the third root of both sides to cancel out the ^3.
= s
