Answer:
28 g CO
Explanation:
First convert grams to moles.
1 mole C = 12.011 g (I'm just going to round to 12 for the sake of this problem)
12 g C • 
= 1 mol C
1 mol O = 15.996 g (I'm just going to round to 16)
16 g O • 
= 1 mol O
So the unbalanced equation is:
-> 
(the oxygen has a 2 subscript because it is part of HONClBrIF meaning when not in a compound these elements appear in pairs - called diatomic elements)
The balanced equation is:
-> 
However, carbon is the limiting reactant in this equation and two moles cannot react because only 12 g (1 mole) are present. Therefore, use the equation
-> .
1 mole of CO is formed, therefore 12 g + 16 g = 28 g CO.
What is the percent yield if 4.65 g of copper is produced when 1.87 g of aluminum reacts with excess copper (II) sulfate? 2Al (s) + 3CuSO4 (aq) → Al2 (SO4)3 (aq) + 3Cu
This question is dealing with the half-life of carbon-14 which can be used to determine the age of a substance according to the following equation:
t = [ln(N/No)/(-ln2)] · t1/2
N = # of carbon-14 atoms presently = 250 atoms
No = # of carbon-14 atoms initially = 1000 atoms
t1/2 = half-life = 5730 years for carbon-14
We can now input all of the information into the formula to find the age of the fossil:
t = [ln (250/1000)/-ln2] x 5730 years
t = 11460 years
The fossil should be found to be roughly 11,460 years old.
Crust, Mantel, Outercore, Innercore
