Answer:
(20/100)×80=16
Step-by-step explanation:
Part of the value of sin(u) is cut off; I suspect it should be either sin(u) = -5/13 or sin(u) = -12/13, since (5, 12, 13) is a Pythagorean triple. I'll assume -5/13.
Expand the tan expression using the angle sum identities for sin and cos :
tan(u + v) = sin(u + v) / cos(u + v)
tan(u + v) = [sin(u) cos(v) + cos(u) sin(v)] / [cos(u) cos(v) - sin(u) sin(v)]
Since both u and v are in Quadrant III, we know that each of sin(u), cos(u), sin(v), and cos(v) are negative.
Recall that for all x,
cos²(x) + sin²(x) = 1
and it follows that
cos(u) = - √(1 - sin²(u)) = -12/13
sin(v) = - √(1 - cos²(v)) = -3/5
Then putting everything together, we have
tan(u + v)
= [(-5/13) • (-4/5) + (-12/13) • (-3/5)] / [(-12/13) • (-4/5) - (-5/13) • (-3/5)]
= 56/33
(or, if sin(u) = -12/13, then tan(u + v) = -63/16)
Answer:
Where are the expression??
Step-by-step explanation:
Garden one and two are both unknown, so I am choosing to call garden 2 X and then label garden 1 with comparisons to X.
It is tempting to list:
Garden Two = X
Garden One = X + 9
BUT there is an easier way. We are told that when 3 bushes are taken from garden 2 (x-3) and put in garden 1 (x + 12) then garden one has 1.5 times more than garden two.
Set it up like this:
1.5 ( x - 3) = x + 12 (because 1.5 times garden 2 will give us garden 1)
1.5x - 4.5 = x + 12 (Distribute)
.5x = 16.5 (Use subtraction to move variables to the right and other numb left)
x = 33 for Garden 2
33 + 9 for Garden 1 = 42
Answer:
4,969.25
Step-by-step explanation:
$19877 ÷ 4
you van either divide this the long way or the short way either one will give you the same answer so just try it out and see
