Question

X^2- 10x +41 = -9 I need it in square form

Answer 1

Answer:

sierravo12 avatar

x^2 - 10x + 41 = 0 ===> a = 1, b = -10, c = 41

x = [-b ± √(b^2 - 4ac)]/(2a)

x = [-(-10) ± √((-10)^2 - 4(1)(41))]/2(1)

x = [10 ± √(100 - 164)]/2

x = [10 ± √(-64)]/2

x = (10 ± 8i)/2

x = 5 ± 4i <===ANSWER

i just found it

Step-by-step explanation: