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belka [17]
3 years ago
10

Factor 54+27 using the gcf What is the factored expression

Mathematics
1 answer:
vazorg [7]3 years ago
3 0
With 9 being the GCF this is what i got <span>9*(6+3)</span>
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Which of the following symbols could correctly finish the statement? select all that apply.
Artemon [7]

Answer:

Part A) the answer is =

Part B) the answer is >

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
When Harper commutes to work, the amount of time it takes her to arrive is normally distributed with a mean of 24 minutes and a
Korvikt [17]

Answer:

\mu -2\sigma = 24-2*3= 18

\mu -2\sigma = 24+2*3= 30

So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case

Step-by-step explanation:

For this case we can define the random variable X as the amount of time it takes her to arrive to work and we know that the distribution for X is given by:

X \sim N(\mu = 24, \sigma =3)

And we want to use the empirical rule to estimate the middle 95% of her commute times. And the empirical rule states that we have 68% of the values within one deviation from the mean, 95% of the values within two deviations from the mean and 99.7 % of the values within 3 deviations from the mean. And we can find the limits on this way:

\mu -2\sigma = 24-2*3= 18

\mu -2\sigma = 24+2*3= 30

So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case

7 0
3 years ago
4 = 3/4m - 6 pls help me ASAP and check the answer
laila [671]

Answer:

m = 3/40

Step-by-step explanation:

4 = 3/4m - 6

m*4 = m(3/4m -6)

4m = m*3/4m + m*-6

4m = 3/4 - 6m

6m + 4m = 3/4

10m = 3/4

m = (3/4)/10

m = 3/40

check:

4 = 3/(4*3/40) - 6

4 = 3/(12/40) - 6

4 = (3*40)/12 - 6

4 = 120/12 - 6

4 = 10 - 6

4 0
3 years ago
Find the probability of exactly three successes in six trials of a binomial experiment in which the the probability of is 50%.
Lyrx [107]

Start by doing the binomial expansion of (x+y)^6 where x represents success. This is

(x^6y^0) + 6(x^5y^1) +15(x^4y^2) +20(x^3y^3) +15(x^2y^4) +6(x^1y^5) +(x^0y^6)

We are interested in the x^3y^3 term which represents exactly 3 sucesses. Since the probalbility of sucess and failure are both .5 we should be able to figure this out just using the coefficients of the terms which is

20/64 = .3125 which is 31.25%

4 0
3 years ago
10. The number of people, N, employed in a chain of cafes is related to the number of cafes, n, by the equation:
il63 [147K]

Answer:

b.

i. N= 10n+120

    = 10*14+120

    = 260

ii. N = 10n+120

<=> 190=10n+120

<=> n=7

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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