Answer:
Part A) the answer is =
Part B) the answer is >
Step-by-step explanation:
Answer:


So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case
Step-by-step explanation:
For this case we can define the random variable X as the amount of time it takes her to arrive to work and we know that the distribution for X is given by:

And we want to use the empirical rule to estimate the middle 95% of her commute times. And the empirical rule states that we have 68% of the values within one deviation from the mean, 95% of the values within two deviations from the mean and 99.7 % of the values within 3 deviations from the mean. And we can find the limits on this way:


So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case
Answer:
m = 3/40
Step-by-step explanation:
4 = 3/4m - 6
m*4 = m(3/4m -6)
4m = m*3/4m + m*-6
4m = 3/4 - 6m
6m + 4m = 3/4
10m = 3/4
m = (3/4)/10
m = 3/40
check:
4 = 3/(4*3/40) - 6
4 = 3/(12/40) - 6
4 = (3*40)/12 - 6
4 = 120/12 - 6
4 = 10 - 6
Start by doing the binomial expansion of (x+y)^6 where x represents success. This is
(x^6y^0) + 6(x^5y^1) +15(x^4y^2) +20(x^3y^3) +15(x^2y^4) +6(x^1y^5) +(x^0y^6)
We are interested in the x^3y^3 term which represents exactly 3 sucesses. Since the probalbility of sucess and failure are both .5 we should be able to figure this out just using the coefficients of the terms which is
20/64 = .3125 which is 31.25%
Answer:
b.
i. N= 10n+120
= 10*14+120
= 260
ii. N = 10n+120
<=> 190=10n+120
<=> n=7
Step-by-step explanation: