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2 years ago

Given f(x) = 3x+5 work out the value for f(2)

Mathematics

2 answers:

kotykmax [81]2 years ago

5 0

Answer:

Step-by-step explanation:

→ f(x) = 3x + 5

→ f(2) = 3(2) + 5

⇒ 6 + 5

⇒11

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bagirrra123 [75]2 years ago

4 0

Answer:

f(2) = 11

Step-by-step explanation:

f(x) = 3x+5

f(2) = 3(2)+5

f(2) = 6+5

f(2) = 11

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7nadin3 [17]

Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

In two or more complete sentences, compare the number of x-intercepts in the graph of f(t) = 12 to the number of x-

alina1380 [7]

Answer:

Both functions have one x-intercept each.

Step-by-step explanation:

The first function is

$f(t )= {t}^{2}$

This is a parabola with vertices at the origin and has one x-intercept at t=0.

The transformed function is

$g(t) = {(t + 3)}^{2}$

The function g(t) is obtained by shifting the graph of f(t) to the left by 3 units.

This graph also has one x-intercept at x=-3.

Therefore both functions has the same number of x-intercepts

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3 years ago

Write the equation of the line perpendicular to the line x - 3y = 9 and passing through the point (3,5).

PilotLPTM [1.2K]

Here is a sample problem
has to be perpendicular to y=(4/9)*x-2 and pass through 4,3,

y-b=m(x-a)
slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore.
y-3=-9/4*(x-4)
y-3=-9/4x+9
y=-9/4x+9+3
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2 years ago

a cashier at the supermarket has $685 in 4 different denomination bills in her register at the end of the day. the number of $5

netineya [11]

9514 1404 393

Answer:

85 ones
70 fives
15 tens
2 fifties

Step-by-step explanation:

Let a, b, c, d represent the numbers of $1, $5, $10, and $50 bills, respectively. The problem statement tells us ...

a +5b +10c +50d = 685 . . . . . total amount of cash

b = 10 +4c . . . . . . . . . . . . the number of fives is 10 more than 4 times tens

a = b+c . . . . . . . . . . . as many ones as fives and tens combined

d = 2 . . . . . . . . . . the register contained 2 fifty-dollar bills

Substituting for 'a', then for 'b', we have ...

(b+c) +5b +10c +50d = 685

6(10 +4c) +11c +50d = 685

60 +35c +50d = 685

Substituting d=2 and subtracting 160 gives ...

35c = 525

c = 15

b = 10 +4c = 10 +4(15) = 70

a = b+c = 70 +15 = 85

The register contained ...

85 ones
70 fives
15 tens
2 fifties

5 0

2 years ago

Read 2 more answers