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4 years ago

please help i don't understand this one i appreciate anyone who helps :) Solve for x. 7x - 3/8 = 6x -

Mathematics

1 answer:

svet-max [94.6K]4 years ago

6 0

Answer:

x = 3/8

Step-by-step explanation:

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What solution is this 2x=3x

Dafna1 [17]

Answer:

there is no solution to this eqn.

this eqn brings us to 2=3 which certainly is false..

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What are the measures of the two angles in the figure below?

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PLEASE HELP!!! I need an urgent answer and I'll give brainiest just please answer this easy question!

Leya [2.2K]

Answer:

y , add 7, multiply by 3, then subtract 6.or Solve the system of equations and choose the correct answer from the list of options. x − y = 7 y = 3x + 12 2 over 19 comma 2 over 33 negative 2 over 19 comma negative 33 over 2 negative 19 over 2 comma negative 33 over 2 19 over 2 comma 33 over 2

Step-by-step explanation:

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3 years ago

Help! Will give brainly! Explain why the value x=4 is not a solution to the inequality 2x>10

melamori03 [73]

Answer

8 is not greater than 10

Step-by-step explanation:

2x>10

2(4)>10

8<10

x=4 can not be the solution to this equation because 8 is less than 10

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3 years ago

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Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

<u>Given equation</u>:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

<u>To complete the square for a hyperbola</u>

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

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2 years ago