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fomenos
2 years ago
6

Will give brainliest if correct.

Mathematics
1 answer:
Allisa [31]2 years ago
8 0
The slope is -5/0. Hope this helps
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XY bisects DF at point E. If DE=2y and EF=8y-3, find the value of DF​
nirvana33 [79]

Answer:

Step-by-step explanation:

If XY bisects DF at point E, then DE = EF.

Given DE = 2y and EF = 8y-3

2y = 8y-3

subtract 8y from both sides

2y-8y = 8y-8y-3

-6y = -3

y = 3/6

y = 1/2

y = 0.5

DF = DE+EF

DF= 2y+8y-3

DF = 10y - 3

DF = 10(0.5)-3

DF = 5-3

DF = 2

7 0
2 years ago
Solve for x. She<br> - 7/2x+ 1/2= 31/6
Lilit [14]
I think it is -3/4 im pretty sure
8 0
3 years ago
#2
I am Lyosha [343]

You have the right idea that things need to get multiplied.

What should be done is that the entire fraction needs to get multipled by the lowest common denominator of both denominators.

Let's look at the complex numerator. Its denominators are 5 and x + 6. Nothing is common with these, so both pieces are needed.

The complex denominator has x - 3 as its denominator. With nothing in common between it and the complex numerator, that piece is needed.

So we multiply the entire complex fraction by (5)(x + 6)(x -3).

Numerator: (\frac{1}{5} -\frac{5}{x + 6})(5)(x +6)(x-3) =\frac{1}{5}(5)(x +6)(x-3) -   \frac{5}{x + 6}(5)(x +6)(x-3)

= (x+6)(x-3) - (5)(5)(x-3)

= (x+6)(x-3) - 25(x-3)

= (x-3)(x + 6 - 25) <--- by group factoring the common x - 3

= (x -3)(x - 19)

Denominator:

\frac{25}{x - 3} * (5)(x + 6)(x - 3) = (25)(5)(x + 6) = 125(x + 6)


Now we put the pieces together.


Our fraction simplies to (x - 3) (x - 19) / 125 (x + 6)

5 0
3 years ago
In a state where license plates contain six digits, what is the probability that the license number of a randomly selected car h
andre [41]

Answer:

Step-by-step explanation:

Given : In a state where license plates contain six digits.

Probability of that a number is 9 = \dfrac{1}{10}   [Since total digits = 10]

We assume that each digit of the license number is randomly selected  .

Since each digit in the license plate is independent from the other  and there is only two possible outcomes for given case (either 9 or not), so we can use Binomial.

Binomial probability formula:  P(X=x)=^nC_xp^x(1-p)^{n-x}

, where n= total trials , p = probability for each success.

Let x be the number of 9s in the license plate number.

X\sim Bin(n=6, p=\dfrac{1}{10}})

Then, the probability that the license number of a randomly selected car has exactly two 9's will be :

P(X=2)=^6C_2(\dfrac{1}{10})^2(1-\dfrac{1}{10})^{6-2}\\\\=\dfrac{6!}{2!(6-2)!}(\dfrac{1}{100})(\dfrac{9}{10})^4=0.098415

Hence, the required probability = 0.098415

5 0
3 years ago
GCF of 9ab^2 and 6bc^2
Alchen [17]

For this case we have that by definition, the GCF (Greatest Common Factor) is the largest integer that divides the numbers.

We have the following expressions:

9ab ^ 2\\6bc ^ 2

We find the factors of 9 and 6:

9: 1,3,9\\6: 1,2,3,6

Thus, the largest number that divides 9 and 6 is 3

It is also observed that "b" is the common variable of both expressions

Therefore, the GCF of the expressions is:

3b

Answer:

3b

8 0
3 years ago
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