Answer:
Step-by-step explanation:
If XY bisects DF at point E, then DE = EF.
Given DE = 2y and EF = 8y-3
2y = 8y-3
subtract 8y from both sides
2y-8y = 8y-8y-3
-6y = -3
y = 3/6
y = 1/2
y = 0.5
DF = DE+EF
DF= 2y+8y-3
DF = 10y - 3
DF = 10(0.5)-3
DF = 5-3
DF = 2
I think it is -3/4 im pretty sure
You have the right idea that things need to get multiplied.
What should be done is that the entire fraction needs to get multipled by the lowest common denominator of both denominators.
Let's look at the complex numerator. Its denominators are 5 and x + 6. Nothing is common with these, so both pieces are needed.
The complex denominator has x - 3 as its denominator. With nothing in common between it and the complex numerator, that piece is needed.
So we multiply the entire complex fraction by (5)(x + 6)(x -3).
Numerator: 
= (x+6)(x-3) - (5)(5)(x-3)
= (x+6)(x-3) - 25(x-3)
= (x-3)(x + 6 - 25) <--- by group factoring the common x - 3
= (x -3)(x - 19)
Denominator:

Now we put the pieces together.
Our fraction simplies to (x - 3) (x - 19) / 125 (x + 6)
Answer:
Step-by-step explanation:
Given : In a state where license plates contain six digits.
Probability of that a number is 9 =
[Since total digits = 10]
We assume that each digit of the license number is randomly selected .
Since each digit in the license plate is independent from the other and there is only two possible outcomes for given case (either 9 or not), so we can use Binomial.
Binomial probability formula: 
, where n= total trials , p = probability for each success.
Let x be the number of 9s in the license plate number.

Then, the probability that the license number of a randomly selected car has exactly two 9's will be :

Hence, the required probability = 0.098415
For this case we have that by definition, the GCF (Greatest Common Factor) is the largest integer that divides the numbers.
We have the following expressions:

We find the factors of 9 and 6:

Thus, the largest number that divides 9 and 6 is 3
It is also observed that "b" is the common variable of both expressions
Therefore, the GCF of the expressions is:

Answer:
