Answer:
You didn't provide a image of the problem how am I suppose to help you
Answer:
-1/2
Step-by-step explanation:
lim x-> π/2 cos x /(2x-π) =
lim (x-π/2)->0 sin (π/2 - x) /2(x-π/2) =
lim (x-π/2)->0 - sin (x - π/2)/2(x-π/2) = -1/2
Answer:
The distance is:
Step-by-step explanation:
We re-write the equation of the line in the format:
Notice we divided the fraction of y by 2/2, and the fraction of z by 3/3.
In that equation, the director vector of the line is built with the denominators of the equation of the line, thus:
Then the parametric equations of the line along that vector and passing through the point (-2, 3, -4) are:
We plug them into the equation of the plane to get the intersection of that line and the plane, since that intersection is the image on the plane of the point (-2, 3, -4) parallel to the given line:
Then we solve that equation for t, to get:
Then plugging that value of t into the parametric equations of the line we get the coordinates of the intersection:
Then to find the distance we just use the distance formula:
So we get:
Answer:
(a) 0.9412
(b) 0.9996 ≈ 1
Step-by-step explanation:
Denote the events a follows:
= a person passes the security system
= a person is a security hazard
Given:
Then,
(a)
Compute the probability that a person passes the security system using the total probability rule as follows:
The total probability rule states that:
The value of P (P) is:
Thus, the probability that a person passes the security system is 0.9412.
(b)
Compute the probability that a person who passes through the system is without any security problems as follows:
Thus, the probability that a person who passes through the system is without any security problems is approximately 1.
In form
ax+by=c
slope=-a/b
y intercpept=c/b
so
-3x-4y=-12
a=-3
b=-4
c=-12
slope=-(-3)/-4=3/-4=-3/4
yint=-12/-4=3
slope=-3/4
yint is 3