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Firdavs [7]
3 years ago
14

I need help!!!!!! Help Needed!!!!

Mathematics
1 answer:
tatiyna3 years ago
5 0

help with what? be sure to put everything you need to say into a question

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What is the sum of the infinite geometric series?
Alexandra [31]

Answer:

-288

Step-by-step explanation:

n=1/2 divided by -144. You then just plug that number which is .00347 into n in the equation and use a scientific calculator to find the answer.

3 0
4 years ago
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ANYONE HELP FOR THESE AND CAN U EXPLAIN HOW TO DO IT
aleksley [76]
On your X-axis, go to -5 and identify which Y-coordinate it is. For this problem, it would be -2.
4 0
4 years ago
What are the dimensions of the pond? Please help.
balu736 [363]

Let's assume

length of box is l

width of box is w

we know that

area of rectangle = length*width

21=l*w...................(1)

now, we are given

fencing length is 20 foot

fencing length will be equal to perimeter

and we know that

perimeter=2(l+w)

so, we get

2(l+w)=20

now, we can solve for l

l=10-w

now, we can plug that in first equation

21=(10-w)*w

now, we can solve for w

10w-w^2=21

w^2-10w+21=0

(w-7)(w-3)=0

w=7 , w=3

now, we can find length

l=10-3=7

or

l=10-7=3

so, option-B..................Answer

8 0
3 years ago
21 ≤ 3 + 9x please help me solve the inequality
Anastasy [175]

Answer:

x ≥ 2

Step-by-step explanation:

21 ≤ 3 + 9x

21 - 3 ≤ 9x

18 ≤ 9x

18 ÷ 9 ≤ x

2 ≤ x

x ≥ 2

3 0
3 years ago
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In each problem 7 through 14, verify that each given function is a solution of the differential equation. Y" - y = 0; y1(t) = et
Lilit [14]

Answer:

Since L.H.S = R.H.S = 0, for both y_{1} (t) = e^{t} and y_{2} (t) = cosh(t), y₁ and y₂ both satisfy the equation y" - y = 0 and are thus solutions to the differential equation.

Step-by-step explanation:

To check whether the given functions are solutions the given differential equation, we differentiate the functions and then insert it into the given equation.

So y" - y = 0 and  

y_{1} (t) = e^{t}\\y_{1}' (t) = e^{t}\\ y_{1}" (t) = e^{t}

Substituting these values of y and y" into the left hand side of the equation, we have

y" - y  

y_{1}" (t) - y_{1} (t) = e^{t} - e^{t} = 0

Since L.H.S = R.H.S

So y_{1} (t) = e^{t} is a solution of the differential equation.

When

y_{2} (t) = cosh(t)\\ y_{2}'(t) = sinh(t) \\y_{2}"(t) = cosh(t)

Substituting y and y" into the left hand side of the equation, we have

y" - y

y_{2}"(t) - y_{2} (t) = cosh(t) - cosh(t) = 0

Since L.H.S = R.H.S

So, y_{2} (t) = cosh(t) is a solution of the differential equation.

4 0
4 years ago
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