Answer:
You have to eliminate one of the variables when the equations are added.
A) x + 2y + z = 10
B) 2x -y +3z = -5
C) 2x -3y -5z = 27
We mulutiply A) by 2 then add it to B and C
A) 2x + 4y + 2z = 20 and the sum =
6x = 42 Luckily, the "y" and "z" variables cancel out and we find:
x = 7
Then we use x =7 in calcucating equation A) and B)
A) 2y + z = 3
B) -y + 3z = -19
THEN solve for y and z by eliminating variables.
Step-by-step explanation:
Answer:
See Explanation
Step-by-step explanation:
(a) Proof: Product of two rational numbers
Using direct proofs.
Let the two rational numbers be A and B.
Such that:


The product:




Proved, because 1/3 is rational
(b) Proof: Quotient of a rational number and a non-zero rational number
Using direct proofs.
Let the two rational numbers be A and B.
Such that:


The quotient:

Express as product



Proved, because 3/4 is rational
(c) x + y is rational (missing from the question)
Using direct proofs.
Let x and y be
Such that:


The sum:

Take LCM


Proved, because 7/6 is rational
<em>The above proof works for all values of A, B, x and y; as long as they are rational values</em>
Apply division by 10 when one tenth of a number is required and apply multiplication by 10 when 10 times of a number is required.
<u>Solution:</u>
Need to determine what operation is required to get one-tenth of a number and 10 times of a number
To get one tenth of a number, divide the number by 10.
For example to get one – tenth of 100, divide it by 10, we get 10 as a result.

To get ten times of a number, multiply the number by 10
For example 10 times of 10 = 10 x 10 = 100
Hence apply division by 10 when one tenth of a number is required and apply multiplication by 10 when 10 times of a number is required.
Dude tbh, I’m on the same problem as you and I need help with the answer.!!