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dlinn [17]
3 years ago
7

The arithmetic mean of 10 consecutive even integers is 3. What is the least of these 10 even integers?

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0

Answer:

-6

Step-by-step explanation:

2n can be the smallest integer, and 2n + 18 will be the largest integer.

The sum of this, divided by two, will result in the average/mean.

(2n + 2n + 18)/2 = 3

Multiply each side by 2:

(2n + 2n + 18)/2 ⋅ 2 = 3 ⋅ 2

2n + 2n + 18  =  6

Combine the like terms:

4n + 18 = 6

Subtract 18 from both sides:

4n + 18 - 18 = 6 - 18

4n = -12

Divide each side by 4:

4n/4 = -12/4

n = -3

Since we decided to go by 2n:

2n = 2(-3) = <u>-6</u>

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Answer:

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If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?
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Now,

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Since \sin x=\dfrac5{13}, it follows that

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Since x belongs to the first quadrant, you take the positive root (\cos x>0 for x in quadrant I). Then

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\tan x is also positive for x in quadrant I, so you take the positive root again. You're left with

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Plugging the values if x and y the last option is correct 
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