Jughead now earns $10.50 per hour. This is 175% of what he earned last year. How much did he earn last year?

A box of candy bars costs $3.12. Each candy bar in the box costs $0.52. How many candy bars are in the box?

bulgar [2K]

Answer:

6 candy bards

Step-by-step explanation:

$3.12 (total)

each one is $0.52

3.12=0.52b

divide on both sides

3.12/0.52

=6

6 candy bars

(summarized, divide 0.52 by 3.12)

3 0

2 years ago

What’s the gcf of 89 and 64

sergij07 [2.7K]

The greatest common factor is 1

7 0

3 years ago

Read 2 more answers

FAST. As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of

nalin [4]

They will hold 112.25 cm^3 more. Find the volume of the second can with the new side lengths and subtract the orginal volume from the new one.

7 0

1 year ago

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The

zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200, 300

Let X be the total refund payment on the seven day cruise.

We can say X = 0, if there is no rain on all 7 days.

$P(X = 0) = _nC_x * P^x * (1 - P)n-x$

$P(X = 0) = _7C_o * 0.2^0 * (1-0.2)^{7-0$

$P(X = 0) =1 * 1* (1-0.2)^{7$

$P(X = 0) =(0.8)^{7$

$P(X = 0) =0.2097152$

If it rains on any one day; then X = 100

$P(X = 100) = _nC_x * P^x * (1 - P)n-x$

$P(X = 100) = _7C_1 * 0.2^1 * (1-0.2)^{7-1$

$P(X = 0) =7 * 0.2* (1-0.2)^{6$

$P(X = 100) =7* 0.2* (0.8)^{6$

$P(X = 100) =0.3670016$

if it rains on any two day ; then X = 200

$P(X = 200) = _nC_x * P^x * (1 - P)n-x$

$P(X = 200) = _7C_2 * 0.2^2 * (1-0.2)^{7-2$

$P(X = 200) = 21 * 0.2^2 * (0.8)^{5$

$P(X = 200) = 0.2752512$

if it rains on any three day or more than that ; then X = 300

$P(X \ge 300) = 1 - P(X < 300) \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032$

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple $[Var X] =E [X^2] - (E [X])^2$

where;

$E[X^2] = \sum x^2 \times p \\ \\ E[X^2] = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\ E[X^2] = 0 + 3670.016 + 11010.048+ 13322.88 \\ \\ E[X^2] =28002.944$

$(E [X]) = \sum x * p\\ \\ (E [X]) = 0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55$

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

7 0

2 years ago

The temperature of an enclosure for a pet corn snake should be an average of 81° F. For the well-being of the corn snake, the te

mario62 [17]

Answer: |81-x|<5

Step-by-step explanation:

Given: Temperature of an enclosure for a pet corn snake should be an average of 81° F.

Temperature in the enclosure should not vary by more than 5° F.

Let x= Temperature in the enclosure

Then, difference between average and current temperature should less the 5.

i.e. |81-x|<5 (required absolute value equation )

hence, the absolute value equation could be used to determine the minimum and maximum temperatures recommended for the corn snake enclosure:

|81-x|<5

4 0

3 years ago

Jughead now earns $10.50 per hour. This is 175% of what he earned last year. How much did he earn last year?​

Jughead now earns $10.50 per hour. This is 175% of what he earned last year. How much did he earn last year?