The polynomial is (mx^3+3)(2x²+5x+2)-(8x^5 +20x^4)
if it is reduced to 8x^3+6x²+15x+6, so we can find the value of m
(mx^3+3)(2x²+5x+2)-(8x^5+20x^4) = <span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3+6x²+15x+6-8x^5-20x^4=<span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3=8x^3+6x²+15x+6-6x²-15x-6+ <span>8x^5+20x^4
</span>= 8x^5+20x^4+<span>8x^3= 4(2x^5+5x^4+2x^3)
finally
</span>m(2x^5+5x^4+2x^3)=<span>4(2x^5+5x^4+2x^3), and after simplification
</span>
C: m=4
<span>4. When the expression is factored x²-3x-18 completely,
</span>
one of its factor is x-6
<span>x²-3x-18=0
</span>D= 9-4(-18)= 81, sqrtD=9 x=3-9/2= -6/2= -3, and x=3+9 / 2= 6
so <span>x²-3x-18= (x-6)(x+6)
</span>
Answer:
2/3
Step-by-step explanation:
You can try to show this by induction:
• According to the given closed form, we have 
, which agrees with the initial value <em>S</em>₁ = 1.
• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume
and
We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or
From the given recurrence, we know
so that
which is what we needed. QED
Assuming that both triangles are an exact copy of one another, it is safe to assume that 3y-7 is equal to 41. Set up an equation
3y-7=41
Add 7 to both sides
3y=48
Divide both sides by 3
y=16
Now to find PN.
Based on what we know, we can assume that MP = PN. Let's make some equations!
MP = 17x-8 PN = 11x+4
17x-8 = 11x+4
Subtract 11x from both sides
6x-8 = 4
Add 8 to both sides
6x = 12
Divide by 2
x=2
Substitute 2 in for x in the equation for PN
11(2)+4
Multiply 11 by 2
22+4 = 26
PN = 26
I’d need to know the question to answer this.
