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Reptile [31]
3 years ago
15

4. Gilbert works picking strawberries. He

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0

Answer:

Graph is attached

144 baskets

y=2.5x

Step-by-step explanation:

Let y be the total amount of money Gilbert earns and x be the number of baskets filled. So, we get the relation

y=2.5x

Some points which satisfy the equation is

y=2.5\times 1\\\Rightarrow y=2.5

(1,2.5)

y=2.5\times 3\\\Rightarrow y=7.5

(3,7.5)

y=2.5\times 5\\\Rightarrow y=12.5

(5,12.5)

His goal is to earn $360 so y=360

360=2.5x\\\Rightarrow x=\dfrac{360}{2.5}\\\Rightarrow x=144

Hence, to earn $360 he must fill 144 baskets.

The algebraic relation is y=2.5x.

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A die is rolled 23 times and the number of twos that come up is tallied. If this experiment is repeated many times, find the sta
Anon25 [30]

The probability of rolling a 2 is 1/6. If X is a random variable representing the number of 2s that are obtained after rolling a die 23 times, then X follows a binomial distribution with success probability p = 1/6 across n = 23 trials.

The variance of a binomial distribution with parameters p and n is n p (1 - p), so the standard deviation in this case would be

√(23 • 1/6 • 5/6) ≈ 1.8

7 0
3 years ago
Given :f(x) =1/x+5 and g(x) =x-2 What are the restrictions of the domain of f(g(x))?
emmainna [20.7K]
I don't know if it's (1/x )+ 5 or 1/(x+5) anyways
g(x) = x-2 so in f(g(x)) you replace every x with x-2
f(g(x)) = (1/(x-2)) + 5 or 1/(x-2-5) = 1/(x-7)
if the function is like the first form so you avoid numbers which will make your denominator equals zero
x-2 = 0, x=2 or x-7 = 0, x=7
so if it's like first one answer is R - 2
if it's second answer is R - 7
5 0
3 years ago
Read 2 more answers
Carlton and Leon are expert bowlers. Seventy percent of Carlton's rolls are strikes, while 67% of Leon's rolls are strikes. Supp
IgorC [24]

Answer:

The probability that Leon strikes is greater than Carlton strike is 0.40905

Step-by-step explanation:

From the question, we have;

The percentage of Carlton's rolls are strikes, \hat p_1 = 70%

The number of games Carlton played, n₁ = 25

The percentage of Leon's rolls that are strikes, \hat p_2 = 67%

The number of games Leon played, n₂ = 25

Therefore, we have;

\hat p=\dfrac{k_1 + k_2}{n_1 + n_2}

Where;

k₁ = 0.7 × 25 = 17.5

k₂ = 0.67 × 25 = 16.75

\therefore \hat p=\dfrac{17.5 + 16.75}{25 + 25} = 0.685

The test statistic is given as follows;

Z=\dfrac{\hat{p}_1-\hat{p}_2}{\sqrt{\hat{p} \cdot (1-\hat{p})\cdot \left (\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}  \right )}}

Z=\dfrac{0.7-0.67}{\sqrt{0.685 \cdot (1-0.685)\cdot \left (\dfrac{1}{25}+\dfrac{1}{25}  \right )}} \approx 0.2283

From the z-table, we have;

The p-value for Carlton strikes is greater than Leon's strike = 0.59095

∴ The p-value for Leon strikes is greater than Carlton strike = 1 - 0.59095 = 0.40905

The probability that Leon strikes is greater than Carlton strike = 0.40905

8 0
3 years ago
(2/3 - 3/4 × 1/8) ÷ (2/3 - 3/4 + 5/8)
kati45 [8]
<h3>Given:</h3>

( \frac{2}{3}  -  \frac{3}{4}  \times  \frac{1}{8} ) \div ( \frac{2}{3}  -  \frac{3}{4}  +  \frac{5}{8} )

<h3>Solution:</h3>

First, solve the brackets.

First bracket:

( \frac{2}{3}  -  \frac{3}{4}  \times  \frac{1}{8} )

=  \frac{55}{96}

Second bracket:

( \frac{2}{3}   - \frac{3}{4}  +  \frac{5}{8} )

=  \frac{13}{24}

Then divide.

\frac{55}{96}  \div  \frac{13}{24}

=  \frac{55}{52}  \: or \:  1\frac{3}{52}

3 0
2 years ago
Read 2 more answers
Please help me will give brainliest
AnnyKZ [126]

Answer:

you can do \frac{3}{2}x + \frac{1}{2}x + x = 180 or you can do 3x = 180

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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