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Elena L [17]
3 years ago
14

The day length in Manila, Philippines, varies over time in a periodic way that can be modeled by a trigonometric function.

Mathematics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

  • L(t) = 727.775 -51.875cos(2π(t +11)/365)
  • 705.93 minutes

Step-by-step explanation:

a) The midline of the function is the average of the peak values:

  (675.85 +779.60)/2 = 727.725 . . . minutes

The amplitude of the function is half the difference of the peak values:

  (779.60 -675.85)/2 = 51.875 . . . minutes

Since the minimum of the function is closest to the origin, we choose to use the negative cosine function as the parent function.

Where t is the number of days from 1 January, we want to shift the graph 11 units to the left, so we will use (t+11) in our function definition.

Since the period is 365 days, we will use (2π/365) as the scale factor for the argument of the cosine function.

Our formula is ...

  L(t) = 727.775 -51.875cos(2π(t +11)/365)

__

b) L(55) ≈ 705.93 minutes

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Step-by-step explanation:

You want to find an angle that is coterminal to 495. So, subtract 360 degrees until youre in the range of 0-360. I got 495 - 360 = 135°

Tangent is equal to \frac{sin(theta)}{cos(theta)}, we already solved theta which was 135°

This next part is hard to explain to someone who doesnt know their trig circle, idk if you do. The angle 135 is apart of the pi/4 gang. So we know this is going to be some variant of √2/2. Sine of quadrant 1 and 2 is gonna be positive:

sin135=\frac{\sqrt{2} }{2}

Now lets do cosine of 135°, which again is apart of the pi/4 gang because its divisible by 45°. Its in quadrant 2 so the cosine will be negative.

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