Hello:
let : f(x) = <span>x3 − 6x2 + kx + 10
</span><span>If (x + 2) is a factor of x3 − 6x2 + kx + 10 : f(-2) = 0
(-2)^3-6(-2)² +k(-2)+10=0
-8 -24-2k +10 = 0
-2k =8+24-10
-2k = 22
k = -11</span>
Answer:
105
the whole triangle adds up to 180
72+3=75
180-75=105
8.50x+100=308.25
subtract 100 from both sides
8.5x = 208.25
divide 8.5 from both sides
x= 24.5 hours worked
Answer: -1
Step-by-step explanation:
You want to find an angle that is coterminal to 495. So, subtract 360 degrees until youre in the range of 0-360. I got 495 - 360 = 135°
Tangent is equal to
, we already solved theta which was 135°
This next part is hard to explain to someone who doesnt know their trig circle, idk if you do. The angle 135 is apart of the pi/4 gang. So we know this is going to be some variant of √2/2. Sine of quadrant 1 and 2 is gonna be positive:

Now lets do cosine of 135°, which again is apart of the pi/4 gang because its divisible by 45°. Its in quadrant 2 so the cosine will be negative.

The final step is to divide them. They are both fractions so you should multiply by the reciprocal.
