Answer:
67
Step-by-step explanation:
there are 6 birds and you add 7 and this is what you get
Answer:
c
Step-by-step explanation:
Split up the interval [2, 5] into

equally spaced subintervals, then consider the value of

at the right endpoint of each subinterval.
The length of the interval is

, so the length of each subinterval would be

. This means the first rectangle's height would be taken to be

when

, so that the height is

, and its base would have length

. So the area under

over the first subinterval is

.
Continuing in this fashion, the area under

over the

th subinterval is approximated by

, and so the Riemann approximation to the definite integral is

and its value is given exactly by taking

. So the answer is D (and the value of the integral is exactly 39).
Answer:
Putting the value in x = 2 , y =4 in 2x - 2y we get,
2 × 2 - 4× 2= 4-8 = -4
Putting the value in z = 3 in z - 5 we get,
z - 5 = 3 - 5 = -2