1. Let x = #
2. "Five less than six times a number" can be written as: 6x - 5
3. "is at least" is the same as "greater than or equal to" and can be written as: >=
4. "nine subtracted from two times that number" can be written as: 2x - 9
5. the equation is: 6x - 5 >= 2x - 9
6. solve for x by grouping the x variable terms on one side and the constants on the other side:
6x - 5 >= 2x - 9
-2x +5 -2X +5
4x >= -4
7. divide each side by 4, and you get: x = -1
You see what the average is in each class. (Divid students and classes) and add them together and divid by four. You should get 18 if you round to the whole number.
Converse M^Q for # 3
converse M^VxP for #5
converse<_VxT ^ -M
Answer:
11 and 18
Step-by-step explanation:
if the smaller number is a
the larger number is a+7
their sum a + (a+7) = 29
2a + 7 = 29
2a = 29-7
2a = 22
a = 22/2
a = 11
the smaller number is 11
the larger number is 11 + 7 = 18
